Cathy has a nickel, a dime, and a quarter in her purse. She randomly picks a coin, replaces it, and then picks another coin. The
2 answers:
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Answer:
a) P(three tails) =
b) P(two tails followed by one head) =
Step-by-step explanation:
coin is tossed three times so, outcome is
HHH, TTT, HTH, THH, HHT, THT, TTH, HTT.
Hence sample space will be
S = {HHH, TTT, HTH, THH, HHT, THT, TTH, HTT}
chance of getting three tails is '1' i.e. TTT
hence,
P(three tails) =
two tails followed by one head is TTH
so, chance of getting that outcome is also '1'
hence,
P(two tails followed by one head) =
So attached is a picture of the triangle you are talking about and listed under are the choices:
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
<span>D.) Tan Z=a/b
</span>
The answer would then be B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= <u> b </u> CosX =<span><u> a </u></span> TanX=<span><u> b </u></span>
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
<span>D.) Tan Z=a/b
</span>
The answer would then be B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= <u> b </u> CosX =<span><u> a </u></span> TanX=<span><u> b </u></span>
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.