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Marizza181 [45]
3 years ago
12

Cathy has a nickel, a dime, and a quarter in her purse. She randomly picks a coin, replaces it, and then picks another coin. The

probability that the two coins are of different denominations is .
SOMEONE HELP PLEASE THIS IS FOR PLATO.
Mathematics
2 answers:
satela [25.4K]3 years ago
6 0

You could 3•2 because your it two times =6 than it’s 2\6 make more smaller 1/3 it will be. Than you get .3333 repeating

enyata [817]3 years ago
3 0
<h2>Answer:</h2>

Hence, the probability that the two coins are of different denomination is:

                            2/3

<h2>Step-by-step explanation:</h2>

Let N denote nickel, D denotes dime and Q denotes Quarter.

Now when two coins are drawn one after the other with replacement then the outcomes is given by:

         (N,N)     (N,D)      (N,Q)

         (D,N)     (D,D)      (D,Q)

         (Q,N)     (Q,D)      (Q,Q)  

This means that there are a total of  9 outcomes.

The outcomes such that both the denominations are different i.e. the number of favorable outcomes are:  6

{ (N,D) (N,Q) (D,N) (D,Q) (Q,N) (Q,D) }

The probability that the two coins are of different denomination is:

                             6/9=2/3

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If you want to solve this problem using formulas, there are two important formulas:

t1  =  first term  =  -5          

tn  =  nth term  =  last term  =  -5

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So ur answer rounds up to 450


Letter c

:)

hope i helped 


~Luis

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