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3 years ago

Neeeddd soommee helllllpppp

Mathematics

2 answers:

Fed [463]3 years ago

8 0

Buy just looking I'm pretty sure that the last one is a triple. you should see if the others too.

tatyana61 [14]3 years ago

7 0

If they are then

a^2 = b^2 + c^2 where a is the greatest number and b and are the other 2 sides.

The first one is a triple because 26^2 = 10^2 + 24^2

Also 9 40 and 41 are , and the last one.

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Which doesn’t belong? PLEASE HELP! I will give a thanks! helpppppp

Basile [38]

Answer:

The blu

Step-by-step explanation:

It is parallel, while the others are not.

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3 years ago

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Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

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2 years ago

If x2 = 30, what is the value of x? (5 points)

marshall27 [118]

Answer:

It's C.

Step-by-step explanation:

√(30) to the power of 2 is equal to 30.

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2 years ago

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AysviL [449]

The answer is for x is x = 60

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3 years ago

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What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C

butalik [34]

ANSWER

$10C_5(2)^{5}( - 3)^5$

EXPLANATION

The given binomial expansion is:

${(2x - 3y)}^{10}$

Compare this to

${(a + b)}^{n}$

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

${x}^{5} {y}^{5}$

This implies that, r=5.

The terms in the expansion can be obtained using

$T_{r+1}=nC_ra^{n-r}b^r$

We substitute the given values to obtain;

$T_{5+1}=10C_5(2x)^{10-5}( - 3y)^5$

$T_{6}=10C_5(2x)^{5}(3y)^5$

$T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5} {y}^{5}$

Hence the coefficient is;

$10C_5(2)^{5}( - 3)^5$

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3 years ago

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