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Artemon [7]
3 years ago
8

What is the image of point (-7, 7) for mapping (x, y) , (x – 1, x + 6).

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0
Well you can fill out the equation (-7-1, 7+6)
it'll give you 
(-8,13) 
I believe that is what you are asking for :)
Good Luck
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A second number is 6 less than a first number. A third number is twice the first number. If the sum of three number is 306, find
Serga [27]

Answer:

first number = 78

second number = 72

third number = 156

Step-by-step explanation:

first number = a

second number = b

third number = c

we have

b=a-6   equation 1

c=2a     equation 2

a+b+c=306    equation 3

using equation 1 and equation 2 in equation 3 we have

a+a-6+2a=306

4a=306+6

4a=312

a=312/4

a=78= first number

b=78-6=72=second number

c=2*(78)=156 third number

3 0
3 years ago
The width of a swimming pool is one third of its length.The width of the pool is 15 feet.What is the length of the pool?Write an
zubka84 [21]
The answer is 45

Here is why: 15*3=45
5 0
3 years ago
The volume of a rectangular prism can be computed using the formula V = lwh.
olganol [36]

Answer:

13cm

Step-by-step explanation:

substitute values we have into the formula:

1664 = 16 x w x 8

rearrange:

1664/16×8 = w

which equals 13

3 0
2 years ago
Read 2 more answers
Find the sum. Write your answer in simplest form. 3/7 + 2/3​
Delicious77 [7]

Answer:

1 2/21

Step-by-step explanation:

We start out with:

3/7 + 2/3

In order to add them together, they must have an equal denominator. An easy way to find an equal denominator is the cross method. We divide 7 by 3 and 3 by 7, giving us a denominator of 21:

3/21 + 2/21

But what about the numerators? You do the same thing as before (multiplying by the other's denominator).  Now we have:

9/21 + 14/21

We add both together (the denominator stays the same) and we get 23. 23/21 is correct but not in simplest form. We remove 21 from the numerator (because it is a whole) and finally get:

1 2/21!

≧◡≦

Mocha here! If this answer helped you, please consider giving it brainliest because I would appreciate it greatly. Have a wonderful day!

3 0
3 years ago
what is the solution to set to the inequality (4x-3)(2x-1)_>0 a) {x|x<_3 or x_>1} b) {x|x<_2 or x_> 4/3} c) {x|x&
Vinil7 [7]
       (4x - 3)(2x - 1) ≥ 0
4x - 3 ≥ 0    or    2x - 1 ≤ 0
    + 3  + 3                + 1 + 1
     4x ≥ 3                 2x ≤ 1
      4     4                  2    2
       x ≥ ³/₄                  x ≤ ¹/₂
        x ∈ [-∞, ¹/₂] ∧ [³/₄, ∞]

The answer is C.
6 0
3 years ago
Read 2 more answers
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