Answer:
Fifth degree polynomial
Step-by-step explanation:
Given data:
e^0.3
error = 0.0001
let the function ; f(x) = e^x
note : x = 0.3
The Maclaurin polynomial f(x) = e^x = 1 + x + x^2 / 2! + x^3/3! --- + ∑ x^n/n!
= 1 + 0.3 + (0.3)^2/2! + (0.3)^3 / 3! --- + ∑ (0.3)^n/n!
Attached below is the remaining part of the solution
