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mina [271]
3 years ago
10

Find the total cost for a meal that costs $65 with 3% tax.

Mathematics
2 answers:
olga55 [171]3 years ago
5 0

Answer:

total cost =

65/100 X 103= $66.95

Rudik [331]3 years ago
5 0

Answer:

$69.88

Step-by-step explanation:

Firstly, divide the tax rate by 100: 3%/100 = 0.0003 (tax rate as a decimal). Note: to easily divide by 100, just move the decimal point two spaces to the left.

Now, find the tax value by multiplying tax rate by the before tax price:

tax = 65 × 0.0003

tax = 4.88 (tax value rouded to 2 decimals)

Add tax to the before tax price to get the final price:

The final price including tax = 65 + 4.88 = 69.88

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If the mean of 20, y, 10,5,15 is 22 find the value of y​
QveST [7]
Looks like 14.4 because you have to add them all together and divide by the total numbers
(20+22+10+5+15)/ 5
8 0
3 years ago
Find x for the problem
sweet [91]

Answer:

I would say 12 but I am not positive

Step-by-step explanation:

7 0
3 years ago
1. The formula for the volume of a cube is s³. If you have a cube that has a side length,s,
Vesna [10]

Answer

1.8/125 cm³

2. 13

3a. x³-17

3b. 3x-5

5. A) Power

Step-by-step explanation:

1. (2/5)³= 2/5 * 2/5 * 2/5

= 4/25 *2/5

=8/125

2. b³+(10-a)

= (2)³ + (10-5)

=(2*2*2) + (5)

= 8 + 5

= 13

3a. a number cubed = x³

seventeen  less than = -17

3b. three times a number = 3x

five = 5

5. product is when two values are multiplied (13 and 3+x)

6 0
3 years ago
Read 2 more answers
You have are fat<br> a) YES<br> b) no
alina1380 [7]
No but are you fat ???
8 0
3 years ago
2x-y=-1 , 3x-y=2 solve by substition
Mazyrski [523]

Answer:

x = 3, y = 7

or (3,7)

Step-by-step explanation:

We are given the system of equations below:

\large{ \begin{cases} 2x - y =  - 1 \\ 3x - y = 2 \end{cases}}

We are required to solve the system by substitution method. What we have to do is to isolate either x-term or y-term so we can use the method. I will be isolating y-term because it is faster due to having 1 as a coefficient.

By isolating y-term, just pick one of the given equations to isolate. No need to isolate the whole system. (I will be isolating y-term of the first equation.)

\large{ \begin{cases} y=  2x + 1\\ 3x - y = 2 \end{cases}}

Then we substitute y = 2x+1 in the second equation.

\large{3x - (2x + 1) = 2}

Use the distribution property.

\large{3x - 2x - 1 = 2}

Isolate x-term to solve the equation.

\large{x = 2 + 1} \\  \large{x = 3}

Since we are solving a system of equations. We have to solve for both x-value and y-value to complete. We have already found x-value, but nor y-value yet. Therefore, our next step is to substitute the value of x that we solved in any given equations. It's recommended to substitute in an equation that doesn't have high coefficient value. So I will be substituting x = 3 in the first equation.

\large{2x - y =  - 1}  \\  \large{2(3) - y =  - 1} \\  \large{6 - y =  - 1}

Isolate and solve for y-term.

\large{6 + 1 = y} \\  \large{7 = y} \\  \large{y = 7}

Since we substitute x = 3 and get y = 7. We can write in ordered pairs as (3,7)

Hence, the solution is (3,7)

7 0
3 years ago
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