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s2008m [1.1K]
3 years ago
7

Write an equation to represent: four-fifths of z added to six equals eight

Mathematics
1 answer:
finlep [7]3 years ago
6 0
A would be the answer
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I'll mark brainliest thanks in advance ​
dezoksy [38]

Answer:

x = 2

Step-by-step explanation:

These are known as alternate exterior angles. These types of angles are equal to each other.

8x-7=2x+5\\6x-7=5\\6x=12\\x=2

8 0
2 years ago
Forty-two divided by seven plus the quantity three divided by six
ikadub [295]

Answer:

i think its 6.5

Step-by-step explanation:

42/7 = 6

3/6 = 0.5

6+0.5=6.5

6 0
3 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!​
marusya05 [52]

Answer:

5/6 and 6/7

Step-by-step explanation:

In the top of the fraction its going up by one each time (1,2,3,4 so the 5 and 6 would be the top half of the fraction), and in the bottom half its also going up by one but it started at 2 so its one more than the top half  (2,3,4,5, so the 6 and 7 would be the bottom half of the fraction)

4 0
3 years ago
Read 2 more answers
A realtor is studying the graph above, which shows the expected value of properties in her area over the next 24 years. If t rep
sleet_krkn [62]

Answer:

2030

Step-by-step explanation:

the graph starts to decline 16 years after 2014 so 2014 + 16 = 2030

7 0
3 years ago
How do i even solve this?? i’m super confused anything would help. ty.
alukav5142 [94]

Answer:

{b}^{4}  + 1

Your teacher messed up the question so just put the top right answer and ask your teacher if they did accidently miss-type.

Step-by-step explanation:

The first thing to do in this equation is look at the exponents. When multiplying a variable (or any number equal to itself with the same exponent) you only have to add the exponent. So for a, you would add the exponents to get 0, so a to the power of 0 is 1, because any number to the power of 0 is 1. For b, we would add the 3 and 1. (When no exponenet is present in a number then it is 1, so for this I added 3 and 1). So it would be 4. The correct answer is

{b}^{4}  + 1

5 0
2 years ago
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