(solve) 12 1/2-(-4 1/2) =

What is an equation of the line that passes through the point (1,-3) and is perpendicular to the line x+3y=21?

andreev551 [17]

Answer:

3x - y = 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

x + 3y = 21 ( subtract x from both sides )

3y = - x + 21 ( divide all terms by 3 )

y = - $\frac{1}{3}$ x + 7 ← in slope- intercept form

with slope m = - $\frac{1}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{1}{3} }$ = 3 , thus

y = 3x + c ← is the partial equation

To find c , substitute (1, - 3) into the partial equation

- 3 = 3 + c ⇒ c = - 3 - 3 = - 6

y = 3x - 6 ← in slope- intercept form

subtract y from both sides

0 = 3x - y - 6 ( add 6 to both sides )

6 = 3x - y , that is

3x - y = 6 ← in standard form

7 0

3 years ago

The sum of a number and twenty is greater than four times the number decreased by one

Virty [35]

is that the question?

7 0

3 years ago

PLEASE HELP

Tems11 [23]

Answer:

1.

5

x

−

2

y

=

4

; (−1, 1)

2.

3

x

−

4

y

=

10

; (2, −1)

3.

−

3

x

+

y

=

−

6

; (4, 6)

4.

−

8

x

−

y

=

24

; (−2, −3)

5.

−

x

+

y

=

−

7

; (5, −2)

6.

9

x

−

3

y

=

6

; (0, −2)

7.

1

2

x

+

1

3

y

=

−

1

6

; (1, −2)

8.

3

4

x

−

1

2

y

=

−

1

; (2, 1)

9.

4

x

−

3

y

=

1

;

(

1

2

,

1

3

)

10.

−

10

x

+

2

y

=

−

9

5

;

(

1

5

,

1

10

)

11.

y

=

1

3

x

+

3

; (6, 3)

12.

y

=

−

4

x

+

1

; (−2, 9)

13.

y

=

2

3

x

−

3

; (0, −3)

14.

y

=

−

5

8

x

+

1

; (8, −5)

15.

y

=

−

1

2

x

+

3

4

;

(

−

1

2

,

1

)

16.

y

=

−

1

3

x

−

1

2

;

(

1

2

,

−

2

3

)

17.

y

=

2

; (−3, 2)

18.

y

=

4

; (4, −4)

19.

x

=

3

; (3, −3)

20.

x

=

0

; (1, 0)

Find the ordered pair solutions given the set of x-values.

21.

y

=

−

2

x

+

4

; {−2, 0, 2}

22.

y

=

1

2

x

−

3

; {−4, 0, 4}

23.

y

=

−

3

4

x

+

1

2

; {−2, 0, 2}

24.

y

=

−

3

x

+

1

; {−1/2, 0, 1/2}

25.

y

=

−

4

; {−3, 0, 3}

26.

y

=

1

2

x

+

3

4

; {−1/4, 0, 1/4}

27.

2

x

−

3

y

=

1

; {0, 1, 2}

28.

3

x

−

5

y

=

−

15

; {−5, 0, 5}

29.

–

x

+

y

=

3

; {−5, −1, 0}

30.

1

2

x

−

1

3

y

=

−

4

; {−4, −2, 0}

31.

3

5

x

+

1

10

y

=

2

; {−15, −10, −5}

32.

x

−

y

=

0

; {10, 20, 30}

Find the ordered pair solutions, given the set of y-values.

33.

y

=

1

2

x

−

1

; {−5, 0, 5}

34.

y

=

−

3

4

x

+

2

; {0, 2, 4}

35.

3

x

−

2

y

=

6

; {−3, −1, 0}

36.

−

x

+

3

y

=

4

; {−4, −2, 0}

37.

1

3

x

−

1

2

y

=

−

4

; {−1, 0, 1}

38.

3

5

x

+

1

10

y

=

2

; {−20, −10, −5}

Part B: Graphing Lines

Given the set of x-values {−2, −1, 0, 1, 2}, find the corresponding y-values and graph them.

39.

y

=

x

+

1

40.

y

=

−

x

+

1

41.

y

=

2

x

−

1

42.

y

=

−

3

x

+

2

43.

y

=

5

x

−

10

44.

5

x

+

y

=

15

45.

3

x

−

y

=

9

46.

6

x

−

3

y

=

9

47.

y

=

−

5

48.

y

=

3

Find at least five ordered pair solutions and graph.

49.

y

=

2

x

−

1

50.

y

=

−

5

x

+

3

51.

y

=

−

4

x

+

2

52.

y

=

10

x

−

20

53.

y

=

−

1

2

x

+

2

54.

y

=

1

3

x

−

1

55.

y

=

2

3

x

−

6

56.

y

=

−

2

3

x

+

2

57.

y

=

x

58.

y

=

−

x

59.

−

2

x

+

5

y

=

−

15

60.

x

+

5

y

=

5

61.

6

x

−

y

=

2

62.

4

x

+

y

=

12

63.

−

x

+

5

y

=

0

64.

x

+

2

y

=

0

65.

1

10

x

−

y

=

3

66.

3

2

x

+

5

y

=

30

Part C: Horizontal and Vertical Lines

Find at least five ordered pair solutions and graph them.

67.

y

=

4

68.

y

=

−

10

69.

x

=

4

70.

x

=

−

1

71.

y

=

0

72.

x

=

0

73.

y

=

3

4

74.

x

=

−

5

4

75. Graph the lines

y

=

−

4

and

x

=

2

on the same set of axes. Where do they intersect?

76. Graph the lines

y

=

5

and

x

=

−

5

on the same set of axes. Where do they intersect?

77. What is the equation that describes the x-axis?

78. What is the equation that describes the y-axis?

Part D: Mixed Practice

Graph by plotting points.

79.

y

=

−

3

5

x

+

6

80.

y

=

3

5

x

−

3

81.

y

=

−

3

82.

x

=

−

5

83.

3

x

−

2

y

=

6

84.

−

2

x

+

3

y

=

−

12

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A mirror should be centered on a wall. The mirror is 4 feet wide and the wall is 20 feet wide. Which equation helps determine th

Alinara [238K]

A.) x+4+x=20 should be the answer

7 0

2 years ago

HELPPPP PLEASE HELP ME WITH BASIC MATH I REALLY APPRECIATE IT ((WILL MARK AS BRAINLIEST))

Yakvenalex [24]

Answer:

3) 522

4) 468

Step-by-step explanation:

hello!

3) in the question, it says the cross section is a square, and the area of PQRS is 81.

for the square, we know that the length and height have to be the same, so if the area is 81, then we know the sides are both 9 because 9*9 is 81 and they're the same numbers multiplied. (same height and length)

with the information that all 4 sides of the square is 9 and the other side is labeled 10, we can figure out the rest.

both squares : 81+81=162

both 10 by 9 sides: 90+90=180

both 10 by 9 sides (top and bottom): 90+90=180

total surface area=162+180+180=522

4) for this problem, we can see that the triangle is a right triangle.

to solve the area of the triangle, we can do (9*12)/2=108/2=54.

there are two sides with triangles, so we double 54 (54*2=108)

9 by 10 side: 90

10 by 12 side: 120

now for the last slide, theres no information on the length. the formula for the diagonal is

a^2+b^2=c^2

which is

9^2+12^2=81+144=255=15^2

with this, the area of the rectangular side gives us 10*15 which is 150.

adding it together, we get

108+90+120+150=468.

hope this helps!

7 0

3 years ago