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ArbitrLikvidat [17]
4 years ago
7

What is the least common multiple or 8 and 2

Mathematics
2 answers:
Rufina [12.5K]4 years ago
6 0
The <span>least common multiple or 8 and 2 is 8.</span>
Troyanec [42]4 years ago
5 0
The least common mutiple for 8 and 2 is 8 beacause all you have to do is mutiple by 2 and 8 and you get the same least number that is your answer. Sorry for my sucky explaining i hope this helps a little.
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tatuchka [14]
A. 10

because 80 - 10 = 70 & 90 - 2(10) = 70
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3 years ago
True or false Question in picture?
Sunny_sXe [5.5K]

False. b is the y-intercept.

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6 0
3 years ago
Read 2 more answers
12+8 (-5= <br> A:2<br> B:8 <br> C:15<br> D:10
ludmilkaskok [199]

Answer:

The answer is C

Step-by-step explanation:

12+8=20

Then you subtract 20 by 5

8 0
3 years ago
When dante was born, his grandparents deposited $10,000 into a special college fund that paid 4% annual interest, compounded mon
RSB [31]

Using compound interest, it is found that Dante was 6.6 years old when the balance in the account reached $13,000.

<h3>What is compound interest?</h3>

The amount of money earned, in compound interest, after t years, is given by:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

In which:

  • A(t) is the amount of money after t years.
  • P is the principal(the initial sum of money).
  • r is the interest rate(as a decimal value).
  • n is the number of times that interest is compounded per year.

In this problem, we have that the parameters are given as follows:

A(t) = 13000, A(0) = 10000, r = 0.04, n = 12.

Hence the time in years is found as follows:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

13000 = 10000\left(1 + \frac{0.04}{12}\right)^{12t}

(1.0033)^{12t} = 1.3

\log{(1.0033)^{12t}} = \log{1.3}

12t\log{1.0033} =  \log{1.3}

t = \frac{\log{1.3}}{12\log{1.0033}}

t = 6.6

More can be learned about compound interest at brainly.com/question/25781328

#SPJ1

5 0
2 years ago
(7a? - a2 + 4a) + (2a? – Ba? - 4a)
Mademuasel [1]
Answer: 3xy = 1. Example 2: Simplify 7a + 5b - 6b + 8a 2b = 0. Solution: Step 1: group together the like terms
7 0
4 years ago
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