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zzz [600]
3 years ago
12

11xto the 7th power ×6x to the 5th power

Mathematics
1 answer:
solong [7]3 years ago
6 0

The first one is 19,487,171 and the second is 7,776

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Find the area please
Natasha2012 [34]

Answer:

7.07

Step-by-step explanation:

3 0
2 years ago
In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
2 years ago
Lines s and t are perpendicular if the slope of line s is 5 what is the slope of line t
ycow [4]

The slope of line T is -1/5, because perpendicular lines have opposite reciprocal slopes, meaning the opposite sign (positive or negative) and flipped (whole number becomes a fraction).

5 0
3 years ago
Read 2 more answers
Simplify 3 x (7 - 2) + 6
Gnesinka [82]
The answer is 21.

if u look at (7-2) that gives you 5 then 3x5 gives you 15 and then you add 15+6 to get your answer of 21.
8 0
3 years ago
What's is the square root of 63
QveST [7]
You want to be finding out what two factors (where one of them is a perfect square) has the produce of 63. It seems like 9 x 7 (9 is the perfect square) works.

\sqrt{63} =  \sqrt{9 \times 7} = \sqrt{9} \times \sqrt{7}

The square root of 9 is 3 so we can just have 3 \sqrt{7} (which just means 3 times the square root of 7). 

3 0
3 years ago
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