Answer:
Where's the table?
Step-by-step explanation:
Answer:
A. No real solution
B. 5 and -1.5
C. 5.5
Step-by-step explanation:
The quadratic formula is:
, with a being the x² term, b being the x term, and c being the constant.
Let's solve for a.



We can't take the square root of a negative number, so A has no real solution.
Let's do B now.





So B has two solutions of 5 and -1.5.
Now to C!




So c has one solution: 5.5
Hope this helped (and I'm sorry I'm late!)
I'd say that the relationship between y and x is that they're both equivalent to each other, since -3 = -3.
Number of boys enrolled is 105
<em><u>Solution:</u></em>
Given that, At a local preschool there is s as ratio of 3 boys to every 4 girls
There are 245 total preschoolers
Ratio of boys and girls = 3 : 4
Number of boys : number of girls = 3 : 4
Let the number of boys be 3x
Let the number of girls be 4x
Total number of preschoolers = 245
Therefore,
number of boys + number of girls = 245
3x + 4x = 245
7x = 245
x = 35
Number of boys = 3x = 3(35) = 105
Thus number of boys is 105