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JulijaS [17]
3 years ago
15

Some students were surveyed to determine if they prefer soccer or baseball. The results are shown in the two-way table below. Ba

sed on the results of the survey, what percent of the girls surveyed prefer soccer to baseball?
60%


40%


12%


24%

Mathematics
1 answer:
Arada [10]3 years ago
3 0
60% add then divide them 

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I forgot to label the triangle below! I just know that the cos A = 0.48. Based on this information, which angle should be marked
lianna [129]

Answer:

angle 1

Step-by-step explanation:

Using the trigonometric mnemonic SOH CAH TOA, we know that cos or cosine is the ratio between the adjacent side and hypotenuse side.

This means that if cos A = 0.48, A is the measure of the angle which it's relative adjacent side divided by the hypotenuse of the triangle will be around 0.48.

Let's try angle 2, cos (angle 2) = adjacent / hypotenuse = 7.8 / 8.9 = 0.876404494382 ≈ 0.87 ≠ 0.48. Since the proportions are not equal, this angle cannot be the one marked as A.

Since angle 3 is a right angle, the adjacent could be either side so it cannot be correct. Thus angle 1 is correct.

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3 years ago
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Step-by-step explanation:

<h2>A^2 + B^2 = C^2 </h2>

A and B are the legs of the triangles.

C is the hypotenuse.

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-144            -144

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The length of the second leg is 16.

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Step-by-step explanation:

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Prove ΔPAB is isosceles.
Licemer1 [7]

Answer:

See explanation

Step-by-step explanation:

If PX\cong PY, then triangle PXY is isosceles triangle. Angles adjacent to the base XY of an isosceles triangle PXY are congruent, so

\angle 1\cong \angle 2

and

m\angle 1=m\angle 2

Angles 1 and 3 are supplementary, so

m\angle 3=180^{\circ}-m\angle 1

Angles 2 and 4 are supplementary, so

m\angle 4=180^{\circ}-m\angle 2

By substitution property,

m\angle 4=180^{\circ}-m\angle 2=180^{\circ}-m\angle 1=m\angle 3

Hence,

\angle 3\cong \angle 4

Consider triangles APX and BPY. In these triangles:

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so \triangle APX\cong \triangle BPY by ASA postulate.

Congruent triangles have congruent corresponding sides, then

AP\cong BP

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