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BabaBlast [244]
3 years ago
13

Find the sum of the first 27 terms of the sequence: 2.5 + 5.5 + 8.5 + 11.5 + …

Mathematics
1 answer:
melamori03 [73]3 years ago
8 0
2
2.5
5.5
+8.5
11.5
_____
18 .0
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WILL GIVE BRAINLIEST! <br>What is the answer for question (iv)? <br>please help! ​
Leviafan [203]

Step-by-step explanation:

\triangle ABC \sim \triangle ADE... (given) \\\\\therefore \frac {AC}{AE} = \frac {BC}{DE}.. (csst) \\\\\therefore \frac {5}{5+2x} = \frac {x+3}{4x+1}\\ \\ \therefore \: 5(4x + 1) = (5 + 2x)(x + 3) \\ \therefore \:20x + 5 = 5x + 15 + 2 {x}^{2}  + 6x \\ \therefore \:20x + 5 =2 {x}^{2} +  11x + 15 \\ \therefore \:2 {x}^{2} +  11x + 15 -2 0x  - 5 = 0\\  \therefore \:2 {x}^{2}  - 9x + 10 = 0\\ \therefore \:2 {x}^{2}  - 5x   -  4x+ 10 = 0\\ \therefore \:x(2x - 5) - 2(2x - 5) = 0 \\ \therefore \:(2x - 5)(x - 2) = 0 \\ 2x - 5 = 0  \:  \: or \:  \: x - 2 = 0 \\ x =  \frac{5}{2} \:  \:  or \:  \: x = 2 \\ x = 2.5 \:  \: or \: x = 2 \\ x = 2.5 \: is \: largest \\  \\  \frac{A(\triangle ABC)}{ A(\triangle ADE)} =  \frac{AC ^{2} } {AE^{2} } \\  \\ \frac{A(\triangle ABC)}{ A(\triangle ADE)} =  \frac{5 ^{2} } {(5 + 2x)^{2} } \\  =  \frac{25}{(5 + 2 \times 2.5)^{2} }  \\  =  \frac{25}{ {10}^{2} }  \\  =  \frac{25}{100}  \\  \\  \frac{A(\triangle ABC)}{ A(\triangle ADE)} =  \frac{1}{4}  \\

5 0
4 years ago
Lara has a triangle that has side lengths of 26, 34, and 58. She wants to reduce the triangle by one half, so she divides each s
astraxan [27]
<span>the answer is C: Lara should have only divided the side lengths by 2 in order to reduce the triangle.</span>
3 0
3 years ago
Read 2 more answers
The missing term in the denominator is
Margaret [11]

\frac{7^{16} }{7^{12} }= \frac{7^{16-34} }{7^{12-34} } =\frac{7^{-18} }{7^{-22} } = 2401

so the missing term in the denominator is 7^(-22)

ok done. Thank to me :>

5 0
3 years ago
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