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3 years ago

Celeste hiked 1.8miles in 0.75 hour. what is the average of rate of speed

1 answer:

Ivan3 years ago

4 0

To find the average rate of speed, divide:
1.8/0.75 = 2.4

The answer is 2.4.

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)

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HELP!! Question in picture!

Charra [1.4K]

Answer:

factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36

common factors of both:

1, 2, 3, 4, 6, and 12

Please mark me brainliest, so that I get encouraged to make more great answers like this!

4 0

2 years ago

A model rocket was launched from the ground and shot 150 feet straight up.It then fell back down to the ground and landed in the

Elena L [17]

The list of choices you included doesn't have any correct expressions on it.

-- If the rocket went straight up, and then dropped back at the same place
it was launched from, then it must have dropped straight down.

-- The route it followed on the way down was exactly the same as the
route it followed on the way up.

-- Since it reached a maximum height of 150-ft from the ground
and the route was straight, the length of the route was 150-ft.

-- (150-ft going up) plus (150-ft coming down) = 300-ft traveled all together.

8 0

3 years ago

Solve the system and give your answer as a coordinate point in the form (k, c) k+c=100 51k+11c=2500

Aleks [24]

Answer:

k = 35, c = 65

Step-by-step explanation:

Solve the following system:

{c + k = 100 | (equation 1)

{11 c + 51 k = 2500 | (equation 2)

Swap equation 1 with equation 2:

{11 c + 51 k = 2500 | (equation 1)

{c + k = 100 | (equation 2)

Subtract 1/11 × (equation 1) from equation 2:

{11 c + 51 k = 2500 | (equation 1)

{0 c - (40 k)/11 = -1400/11 | (equation 2)

Multiply equation 2 by -11/40:

{11 c + 51 k = 2500 | (equation 1)

{0 c+k = 35 | (equation 2)

Subtract 51 × (equation 2) from equation 1:

{11 c+0 k = 715 | (equation 1)

{0 c+k = 35 | (equation 2)

Divide equation 1 by 11:

{c+0 k = 65 | (equation 1)

{0 c+k = 35 | (equation 2)

Collect results:

Answer: {c = 65 , k = 35

5 0

3 years ago

I have to do a discussion pls help

Pachacha [2.7K]

Answer:

not clear picture

4 0

2 years ago

Read 2 more answers

De 1 kg de queso se utilizaron 1/5 gramos para hacer una pizza y ½ para una tarta ¿Cuántos gramos de queso quedaron? ¿Existe más

Mumz [18]

Answer:

Se usaron 700 g de queso, quedando 300 g de queso.

Step-by-step explanation:

Si se usó 1/5 más 1/2 de queso, el total usado fue:

$\frac{1}{5}+\frac{1}{2}=\frac{7}{10}$

Entonces, se usó 7/10 del kg inicial de queso. Sabiendo que:

1 kg ------ 1000 g

7/10 kg ------ x g

Entonces x = 700 g, lo que significa que se usaron 700 g de queso, quedando 300 g de queso.

Este problema se puede resolver utilizando una regla de tres, como se hizo aquí, o mefiante razones, en una equacion lineal.

Espero te haya sido de ayuda!

4 0

2 years ago