In a triangle the midline joining the midpoints of two sides is parallel to the third side and half as long ⇒
2(3x + 2) = 2x + 20
6x + 4 = 2x + 20
6x - 2x = 20 - 4
4x = 16
x = 16/4
x = 4
midsegment = 3x + 2 = 3*4 + 2 = 12 + 2 = 14
First you have to find 1/3 of the marbles. That means in the twelve marvels she has, there are three even groups. Divide twelve by three and you get four. So if each group is four, it is simple from here on out. If she started out with twelve and she lost 1/3 of them(4) it would be 12-4. You know this because lost is another for for subtract. 12-4=8. She has 8 marbles left.
Answer:
m<ACD = 
Step-by-step explanation:
From the question given, ΔACD is a right angled triangle. Then we can apply one of the properties of a triangle to it.
In the triangle ACD:
<ACD + <DAC + <ADC = 180 (sum of angles in a triangle)
<ACD + 40 + 90 = 180
<ACD + 130 = 180
<ACD = 180 - 130
<ACD =
With the application of the property of the sum of interior angles of a triangle, the measure of <ACD is .
Answer:
Step-by-step explanation: the answer is -2 1/8 or c
Answer:
15, -26
Step-by-step explanation:
The <em>generic solution</em> to a "sum and difference" problem can be found easily. Let "a" and "b" represent the numbers you seek, and let "s" and "d" represent their sum and difference:
a + b = s
a - b = d
Adding these two equations tells you ...
2a = s + d
a = (s + d)/2 . . . . . . divide by the coefficient of a
You can find "b" several different ways. One way is to subtract the second equation from the first:
2b = s - d
b = (s - d)/2 . . . . . . divide by the coefficient of b
So, the second number can be found from any of ...
- b = s - a
- b = a - d
- b = (s - d)/2
____
For the numbers given here, s=-11, d=41, the two numbers are ...
a = (-11 +41)/2 = 15
b = -11 -15 = -26
The two numbers are 15 and -26.
