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3 years ago

How would I add the fractions?

F5" id="TexFormula1" title="-2/5 + 2/3p +1/3p = 2p - 16/5" alt="-2/5 + 2/3p +1/3p = 2p - 16/5" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

LiRa [457]3 years ago

8 0

$\bf -\cfrac{2}{5}+\cfrac{2}{3}p+\cfrac{1}{3}p=2p-\cfrac{16}{5}\implies \stackrel{\textit{LCD of 15}}{-\cfrac{2}{5}+\cfrac{2p}{3}+\cfrac{p}{3}}=\stackrel{\textit{LCD of 5}}{2p-\cfrac{16}{5}}
\\\\\\
\cfrac{(3\cdot -2)+(5\cdot 2p)+(5\cdot p)}{15}=\cfrac{(5\cdot 2p)-16}{5}
\\\\\\
\cfrac{-6+10p+5p}{15}=\cfrac{10p-16}{5}\impliedby \textit{now we cross-multiply}
\\\\\\
-30+50p+25p=150p-240\implies -30+240=150p-75p
\\\\\\
210=75p\implies \cfrac{210}{75}=p\implies \cfrac{14}{5}=p$

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Answer:

(a) Rule: Multiply the input (x) by 2 and add 5 to the result of the product

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Step-by-step explanation:

Given

The attached table

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