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Fantom [35]
3 years ago
9

What is the answer because I really need help and I'm stuck

Mathematics
1 answer:
loris [4]3 years ago
7 0
D
Sq rt of 151 = 12.2/2= 6.14
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There are 7 boys in a class of 15 students ( a ) what is the ratioo of all students in the class to girls? (b) what is the ratio
antiseptic1488 [7]
A:
Ratio of all students in the class to girls is...
15:8

b:
Ratio of boys to girls....
7:8

6 0
3 years ago
Plzz hurry ill give brainliest
abruzzese [7]

Answer:

18c-s

Step-by-step explanation:

Spike. dont. Trust. It

4 0
3 years ago
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Four friends bought tickets to the school play if it cost them a total of $28 find how much each friend paid?
galina1969 [7]

Answer:

28:4=7

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8 0
3 years ago
Steel rods are manufactured with a mean length of 29 centimeter (cm). Because of variability in the manufacturing process, the l
zavuch27 [327]

Solution :

Given data :

The mean length of the steel rod = 29 centimeter (cm)

The standard deviation of a normally distributed lengths of rods = 0.07 centimeter (cm)

a). We are required to find the proportion of rod that have a length of less than 28.9 centimeter (cm).

Therefore, P(x < 28.9) = P(z < (28.9-29) / 0.07)

                                    = P(z < -1.42)

                                   = 0.0778

b). Any rods which is shorter than 24.84 cm or longer than 25.16 cm that re discarded.

Therefore,

P (x < 24.84 or 25.16 < x) = P( -59.42 < z or -54.85)

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4 0
3 years ago
9 to the power 18 = 27 to the power x work out the value of x
Strike441 [17]

Answer:

Step-by-step explanation:

27^x = 9÷(3^x)

So (3^3)^x = (3^2)÷(3^x)

So 3^3x = 3^(2-x)

Comparing powers on both sides,

3x = 2 - x

So, 4x = 2

So, x = 1/2

Given ( 27 ) ^ x = 9 / 3 ^x

⇒ ( 3 × 3 × 3 )^x = ( 3 × 3 ) / 3^x

⇒ ( 3 ³ )^x = 3² / 3^x

⇒  3 ^ 3x × 3^x = 3²            [ since  ( a ^m)^n = a ^mn ]

⇒ 3^ (3x +x) = 3²                [ since a^m × a^n = a ^m+n ]

⇒ 3^4x = 3²

⇒4x = 2                      [ since  If a ^m = a ^n then m = n ]

⇒ x = 2 / 4

 ∴ x = 1 / 2

I hope this helps you.

8 0
3 years ago
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