Answer:
P = 64 cm
Step-by-step explanation:
<C = 150° - 90° = 60°
AB = AC
∠B = ∠C = 60° } => ΔABC = EQUILATERAL TRIANGLE =>
=> BC = 10 cm
P = 10cm + 8cm + 6cm + 10cm + 6cm + 6cm + 8cm + 10cm
P = 3x10cm + 2x8cm + 3x6cm
P = 30cm + 16cm + 18cm
P = 64 cm
Answer:
Step-by-step explanation:
From the given information, we already know two points the line intersects. It states that the line has a y-intercept of 3. The y-intercept is the point at which the line intersects the y-axis. Thus, the line also intersects (0,3). (Remember that all points on the y-axis have an x-value of 0.) Now we have enough information to write an equation.
1) Find the slope of the line with the slope formula,
. Substitute the x and y values of (-5,2) and (0,3) into the formula and solve:

So, the slope of the line is
.
2) Now we can write the equation in slope-intercept form, represented by the formula
. Substitute values for
and
in the formula.
The
represents the slope, so substitute
for it. The
represents the y-intercept, so substitute
for it. This gives the following answer and equation in slope-intercept form:

Answer:
r = 6 mph and f = 11 mph
Step-by-step explanation:
Representations:
1) speed of faster cyclist: f = r + 5
2) speed of slower cyclist: r
Distances covered:
(r + 5)(5 hr) + r(5) = 55 mi (total distance covered)
Then 5r + 25 + 5r = 55, or, after reducing this equation:
r + 5 + r = 11, or
2r = 6
Then r = 6 mph and f = 11 mph
Isn't it 1/8?
I hope this helped i think i just simplified xD
The number of pencils and total cost are in a proportional relationship because the cost increases with the number of pencils.
Option D is correct.
Step-by-step explanation:
The cost of One Pencil = $3
The cost of 3 Pencils = $9
So, as the number of pencils are increasing, the total cost of pencils is also increasing because cost of 1 pencil is $3 and cost of 3 pencils increases to $9
So, we can say that the number of pencils and total cost are in a proportional relationship because the cost increases with the number of pencils.
Option D is correct.
Keywords: Proportional relationship
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