Given that
starting outstanding balance = $150000
rate of interest = 7.5% per year
so rate of interest for 1 month = (7.5/12)% = 0.635%
outstanding balance before 1st monthly payment = starting outstanding balance + 0.625% of interest on starting outstanding balance
= 150000 + (0.625 /100) × 150000
= 150000 + 937.5 = $150937.5
Reduction = outstanding balance after one month - first monthly payment
Reduction = $150937.5 - 1010.10 = 149927.40
so out of first payment of $1,010.10 , $937.5 goes towards interest and remaining $72.6 goes towards reduction of principal that is 150000 - $72.6 = 149927.40.
so correct option is B that is $149927.40.
Maybe 430 or 400 could be the answer to that problem
Answer: MUV OR VUM
Step-by-step explanation:
It is a line so anyway you name it is fine as lomg as its in it's respected order.
Answer:
z is less than 3/4
Step-by-step explanation:
In fact, this problem belongs to the chemistry section. Recall that many other sciences require mathematical calculations. The problem will belong to Mathematics only if no knowledge of other sciences are required to solve the problem.
Solubility for the given substances is measured in grams per 100 g of water at a particular temperature (20 deg.C).
This means that the mass (assumed to be the solute) will not change the solubility, just the minimum quantity of solvent (water) will.
Thus the solubility of sodium chloride will remain L=36 g/100g H2O for any quantity of solute. Similarly, the solubility of lead nitrate will remain as K=54 g/100 g H2O.
The reason that they remain constant is because the quantity of solvent (water) is fixed at 100 g. Varying amount of solute will affect the quantity of solvent required, but not the solubility.
I'll leave it to you to calculate the difference between K & L.