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2 years ago

13

Kevin draws a figure that has four sides.All sides have the same length.His figure has no right angles.What figure does Kevin dr

aw?

1 answer:

svetoff [14.1K]2 years ago

5 0

Rhombus or diamond I think. I hope that this helps!

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PLSSSS HELP<br><br> Choose ALL answers that describe the polygon.

ipn [44]

Answer:

RSTU is a parallelogram, quadrilateral, rectangle, rhombus, and square. NOT trapezoid.

Step-by-step explanation:

The shape has four sides, so it's a quadrilateral.

It has four equal sides so its a rhombus.

It has four right angles so its a rectangle.

It has four equal sides AND right angles so its a square.

And if all the sides are parallel (well, two pairs of parallel sides) its a parallelogram.

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1 year ago

Help me please!! I don't know what to do I'm so confused!!!

lara [203]

Answer: 5/2 + 1/2 = 3/4

Step-by-step explanation: Math...and also the internet ;-;

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2 years ago

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En una caja grande hay 9 cajas dentro de cada una de estas cajas hay 5 cajas, dentro de estas hay 3 cajas. ¿Cuántas cajas hay en

Kazeer [188]

Answer:

34 cajas

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2 years ago

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I need some help please

Monica [59]

Answer:

24

Step-by-step explanation:

The way you calculate the volume of a shape is length x width x height. 4 x 3 x 2 = 24.

3 0

1 year ago

In Example 3, the track has 6 lanes that are each 1 meter in width. a. What is the outer perimeter of the track? Round your answ

son4ous [18]

Answer:

Incomplete question, check attachment for the necessary diagram

Step-by-step explanation:

Note in the attachment,

We have two identical straight line of lenght

L1 = L2 = 84.39m

We also have two identical semicircle or radius 36.5m to the first track lane

But this is not the radius of the circle, the radius of the circle will now be 36.5 plus the 6 track lane and we are told that one track lane is 1m, then, the track lane is 6m

So, radius = 36.5+6

r = 42.5m

Then, we need to calculate the perimeter of the semicircle using the formula of perimeter of a circle and dividing by2

P = 2πr/2

P =πr

P = 22/7 × 42.5

P = 133.57 m

Then, the arc 1 is equal to arc 2 which is equal to 133.57 m

A1 = A2 = 133.57 m

Now we have all the dimensions,

Then, the perimeter can be calculated by adding the length of the sides

The perimeter of the field = Lenght of the two straight lines plus the length of the two semicircle arc

P = L1 + L2 + A1 + A2

P = 84.39 + 84.39 + 133.57 + 133.57

P =435.923 m

So, to the nearest meter

P ≈ 436m

The perimeter of the track is 436m

5 0

2 years ago