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2 years ago

Please help! 100 points and brainlieast if you can help!

Mathematics

1 answer:

zysi [14]2 years ago

5 0

Answer:

1. 38 oz / 2 lbs 6 oz

2. 254 in / 7 yd 2 in

3. 21 pt / 3 gal 2 qt 1 pt

4. 18,480 ft / 3 mi 2,640 ft

5. 180 oz / 6 lbs 12 oz

6. 525 s / 8 min 45 s

7. 318 in / 8 yd 2 ft 10 in (9.99996 inches not simplified)

8. 9 pt / 4 qt 1 pt

9. 15,885 s / 4 hr 24 min 45 s

The first answers are the ones I got originally and the second answers are the simplified ones.

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The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and

brilliants [131]

Answer:

The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

Step-by-step explanation:

The equation of the parabola is:

$y=0.00035x^{2}$

Compute the first order derivative of y as follows:

$y=0.00035x^{2}$

$\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]$

$=2\cdot 0.00035x\\\\=0.0007x$

Now, it is provided that |x | ≤ 605.

⇒ -605 ≤ x ≤ 605

Compute the arc length as follows:

$\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx$

$=\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\$

Now, let

$x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u$

$\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u$

$={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}$

Plug in the solved integrals in Arc Length and solve as follows:

$\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\$

$=1245.253707795227\\\\\approx 1245.25$

Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

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3 years ago

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4 years ago

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Step-by-step explanation:

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3 years ago

In AJKL, the measure of ZL=90°, JL = 55, LK = 48, and KJ = 73. What

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3 years ago

The sum of three numbers is 244.84. One of the numbers is 24.6. The other two numbers are equal to each other. What is the value

mamaluj [8]

Answer:

The value of each of the other two numbers is 110.12

Step-by-step explanation:

244.84 - 24.6 = 220.24

220.24 divided by half is 110.12

The value of the other two numbers is 110.12

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2 years ago