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SashulF [63]
3 years ago
7

If there are five different breads, eight meats, five cheeses, and five special sauces, how many different sandwiches are possib

le?
Mathematics
1 answer:
Papessa [141]3 years ago
6 0

Answer:

There are 1000 different sandwiches possible.

Step-by-step explanation:

The number of breads available is, 5.

The number of meats available is, 8.

The number of cheese available is, 5.

The number of special sauces available is, 5.

Assuming that a person is allowed 1 selection of each category.

The possible number of sandwiches that can be made is:

=5\times8\times5\times5\\=1000

Thus, there are 1000 different sandwiches possible.

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Marysya12 [62]

Answer:

If it cost Hudson $28.20 to send 188 text messages, it would cost $9.45 to send 65 text messages. So the answer would be $9.45.

Step-by-step explanation:

Let me explain why. The answer is 9.45 because, 28.20 divided by 188 is 0.15. Then, if you multiply 0.15 by 63 you get 9.45.
28.20/188=.15

.15x63=9.45
So yeah, that's why if it cost Hudson $28.20 for 188 messages, it would be $9.45 to send 65 messages. So again, the answer is 9.45. I hope this was helpful and makes you understand it more now. :D

6 0
3 years ago
Please please fast I need it fast
Zanzabum

Answer:

0

Step-by-step explanation:

Eliminate the opposite

7 0
3 years ago
Read 2 more answers
Write the equation of the line passing through the point (-2; 2) that is
Brut [27]

Answer:

2y-x-6=0

Step-by-step explanation:

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=1.%20%5Cfrac%7B1%7D%7B3%7D%20%20%2B%20%20%5Cfrac%7B3%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7B6%7D%7B
kondaur [170]

Answer:

1. 3.33333333333

2. -1.3

3. 2.61904761905

4. 2.00833333333

8 0
2 years ago
In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and
Leviafan [203]

Answer:

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

<h3 /><h3>STEP 1:</h3>

Name the probabilities:

p₁ = 0.02,   p₂ = 0.07,   p₃ = 0.91

q₁ = 1-p₁ = 0.98 ,   q₂ = 1-p₂ = 0.93 ,   q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

<h3>STEP 2:</h3>

A.

The function will follow multinomial distribution:

f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})

Substitute the values and make a table.

TABLE IN ATTACHMENT

<h3>STEP 3:</h3>

B.

We calculate marginal distribution by:

P (X=x)= <em>∑</em> P(X=x,Y=y)

fx(x) can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

<h3>STEP 4:</h3><h3>C.</h3>

The mathematic expectation E is the sum of product of each possibility with its probabiity.

E(X)=<em>∑ </em>xP(X=x)

Find E(X):

E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)

E(X)=0.06

<h3>STEP 5:</h3>

Condition probability states:

P(A|B)=\frac{P(A,B)}{P(B)}

It can also be written as:

f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}

Where f_x(1)\\ = 0.057624

Calculate the quotient:

Y|_{x=1} = 0 ,  f_{Y|_X=1 = 0.862245

Y|_{x=1} = 1 ,  f_{Y|_X=1 = 0.132653

Y|_{x=1} = 2 ,  f_{Y|_X=1 = 0.000510

Y|_{x=1} = 3 ,  f_{Y|_X=1 = 0

Find the dependency:

f_{XY}(y)=f_X(x)f_Y(y)

We found that

f_{Y|_X=1 = 0.862245

Calculate f_Y(1) from summing the column from the table

f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141

Which are not equal.

Conclusion:

X and Y are NOT Independent

7 0
4 years ago
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