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2 years ago

Cone A and Cone B are similar. The radius of

Mathematics

1 answer:

PIT_PIT [208]2 years ago

7 0

Answer:

thats funny ahahahaaha

Step-by-step explanation:

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Choose the function that represents the data in the table.

viva [34]

$y = 2 {x}^{2} - 3$

$\huge\underline\mathtt\colorbox{cyan}{Explanation thing:}$

Using hit and trial, you van find it pretty easily-

Putting x=0, we get y=-3
Putting x=1, we get y=-1
Putting x=2, we get y=5

You can try it for yourself as well, for me, I couldn't find any other option appropriate.

4 0

1 year ago

A line has an y-intercept of 4 and a x-intercept of 1. Use this information to write a function in slope intercept form (y = mx

Ad libitum [116K]

Answer: D. y = -4x + 4

Step-by-step explanation:

Notice that the y-intercept is when x is zero and the x intercept is when y is 0.

and to write in the equation in slope intercept form , you will need the slope and the intercept.

We will use the y and x intercepts to find the slope, by find the difference in their y coordinates and dividing it by the difference in their x coordinates.

y intercept: ( 0,4)

x intercept: (1,0)

y coordinates difference: 4 - 0 = 4

x coordinates difference: 0 - 1 = - 1

Slope: 4/-1 = -4

Since the slope is -4 and the the y intercept is 4 , the equation will be

y = -4x + 4

7 0

2 years ago

Which polynomial represents the area of the rectangle?

wel

Answer:

4x2 - 2x - 6

5 0

1 year ago

20 POINTS ANSWER FAST

Monica [59]

I’m pretty sure the answer is (2,1)

8 0

2 years ago

Read 2 more answers

Find the area of a compound shape<br><br> Can you please explain

gtnhenbr [62]

Answer:

$A=292.53~m^2$

Step-by-step explanation:

<u>Area of a Compound Shape</u>

The shape shown in the image is made of two shapes: Half a circle of radius 8 m and a triangle of base 24 m and height 16 m.

The area of a circle of radius r is:

$A_c = \pi r^2$

The area of a triangle of base b and height h is:

$\displaystyle A_t=\frac{b.h}{2}$

Calculate the area of the circle:

$A_c = \pi 8^2$

$A_c = 64\pi$

Area of half the circle:

$A_c/2 = 32\pi~m^2$

Area of the triangle:

$\displaystyle A_t=\frac{24\cdot 16}{2}$

$A_t=192~m^2$

The area of the shaded shape is:

$A=32\pi~m^2+192~m^2$

Substituting the value of pi:

$\mathbf{A=292.53~m^2}$

4 0

2 years ago