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svp [43]
3 years ago
6

Use long division to find the quotient below (30x^3+4x^2-150) / (6x-10)

Mathematics
1 answer:
Anni [7]3 years ago
3 0

Answer:

The answer is

A.5x^2+9x+15

Step-by-step explanation:

kindly find attached the solving for proper understanding and solution flow.

Given Data

the divisor=  6x-10

dividend= 30x^3+4x^2-150

firstly for us to perform the division we need to re write the dividend and include the missing coefficient of x

dividend =30x^3+4x^2+0x-150

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Given the function f(x)=x^2+7x+6f(x)=x
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The average rate of change of the function f( x ) = x² + 7x + 6 at the interval of −4 ≤ x ≤ −1 is 2

<h3>What is the average rate of change the function?</h3>

The average rate of change the function is simply the change in y-values of the two points divided by the change in x-values of the two points.

It is expressed as;

Given the data in the question;

  • f( x ) = x² + 7x + 6
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Average rate of change = ( f(-1) - f(-4) ) / ( (-1) - (-4) )

Average rate of change = ( (-1)² + 7(-1) + 6 ) - ( (-4)² + 7(-4) + 6 ) ) / ( (-1) - (-4) )

Average rate of change = ( (1 + -7 + 6 ) - ( 16 - 28 + 6 ) ) / (-1 + 4 )

Average rate of change = ( ( 0 ) - ( -6 ) ) / (-1 + 4 )

Average rate of change = ( 0 + 6 ) / ( 3 )

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Therefore, the average rate of change of the function is 2.

Learn more about average rate of change here: brainly.com/question/28744270

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