2 rectangle shaped
1) Length = 160 mi ; Width = 40 mi
2) Length = 440 mi - 160 mi ; Width = 240 mi - 70 mi
1 triangle shape
1) base = 70 mi ; height = 440 mi - 160 mi
Area Rectangle 1 = 160 mi * 40 mi = 6,400 mi²
Area Rectangle 2 = 280 mi * 170 mi = 47,600 mi²
Area Triangle 1 = ((440 mi - 160 mi) * 70mi)/2 = (280mi * 70mi)/2 = 9,800 mi²
Total Area = 6,400 mi² + 47,600 mi² + 9,800 mi² = <span>63,800 mi²</span>
Answer:
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Step-by-step explanation:
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1,700 good luck hope it helps you 100*17=1,700
The line through (a,b) with slope m is
y-b = m(x-a)
Here that's
y + 1 = (3/4) (x - 2)
Let's multiply by 4 to clear the fractions and distribute the constants,
4y + 4 = 3x - 6
Rearranging into standard form,
3x - 4y = 10
Check. The slope is 3/4, good. 3(2) - 4(-1) = 6+4 = 10 good
Answer: 3x - 4y = 10
