Answer:
Step-by-step explanation:
![2(x-2)^2=8(7+y)\\2(x-2)^2=56+8y \Rightarrow y={1\over{8}}[2(x-2)^2-56]={1\over{4}}(x-2)^2-7\\finally\\y={1\over{4}}(x-2)^2-7\\let ~change~x~and~y\\x={1\over{4}}(y-2)^2-7\\x+7={1\over{4}}(y-2)^2\\4(x+7)=(y-2)^2\\y-2=\pm\sqrt{4(x+7)}\\\\y=2\pm\sqrt{4x+28}](https://tex.z-dn.net/?f=2%28x-2%29%5E2%3D8%287%2By%29%5C%5C2%28x-2%29%5E2%3D56%2B8y%20%5CRightarrow%20y%3D%7B1%5Cover%7B8%7D%7D%5B2%28x-2%29%5E2-56%5D%3D%7B1%5Cover%7B4%7D%7D%28x-2%29%5E2-7%5C%5Cfinally%5C%5Cy%3D%7B1%5Cover%7B4%7D%7D%28x-2%29%5E2-7%5C%5Clet%20~change~x~and~y%5C%5Cx%3D%7B1%5Cover%7B4%7D%7D%28y-2%29%5E2-7%5C%5Cx%2B7%3D%7B1%5Cover%7B4%7D%7D%28y-2%29%5E2%5C%5C4%28x%2B7%29%3D%28y-2%29%5E2%5C%5Cy-2%3D%5Cpm%5Csqrt%7B4%28x%2B7%29%7D%5C%5C%5C%5Cy%3D2%5Cpm%5Csqrt%7B4x%2B28%7D)
Answer:0.1
Step-by-step explanation:
Answer:
never
Step-by-step explanation:
if it still works then it is not worthless if its super old then it can be a collectors item
<span>7+3i−2−3<span>i
7-2+3i-3i
5+3i-3i
5+0
5 Final Answer
</span></span>
Answer:
9 ⁵⁵⁄₁₀₀ simplified version: 9 ¹¹⁄₂₀
