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krok68 [10]
3 years ago
15

Need help on this problem

Mathematics
1 answer:
Taya2010 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

2(x-2)^2=8(7+y)\\2(x-2)^2=56+8y \Rightarrow y={1\over{8}}[2(x-2)^2-56]={1\over{4}}(x-2)^2-7\\finally\\y={1\over{4}}(x-2)^2-7\\let ~change~x~and~y\\x={1\over{4}}(y-2)^2-7\\x+7={1\over{4}}(y-2)^2\\4(x+7)=(y-2)^2\\y-2=\pm\sqrt{4(x+7)}\\\\y=2\pm\sqrt{4x+28}

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Find the values the thing like beta
VLD [36.1K]

Answer:

β = 110

Step-by-step explanation:

Here, we want to find the value of beta

From the diagram;

70 + β = 180

The reason for this is that the sum of angles on a straight line is 180

Thus, we have that

β = 180-70

β = 110

3 0
3 years ago
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Leto [7]

Answer:

Number of Adult's tickets sold on Saturday = 3,356

Number of Children's tickets sold on Saturday = 2, 928

Total number of tickets sold over these two days is 8,938.

Step-by-step explanation:

Here, the number of tickets sold on FRIDAY:

Adult Ticket sold = 1,678

Children's Tickets sold = 976

So, the total number of tickets sold on Friday  

= Sum of ( Adult + Children's ) tickets  = 1,678  + 976 = 2,654 ....  (1)

The number of tickets sold on SATURDAY:

Adult Ticket sold =   2 times  the number of adult tickets sold on Friday

                            =  1,678 x 2  = 3,356

Children's Tickets sold = 3 times the number of children's tickets sold on Friday.

=  976  x 3 = 2, 928

So, the total number of tickets sold on Saturday  

= Sum of ( Adult + Children's ) tickets  = 3,356 + 2,928 = 6, 284 ....  (2)

Now, the total number of tickets booked in these two days :

Sum of tickets booked on (Friday + Saturday)

= 2,654 +  6, 284  =   8,938

Hence, total number of tickets sold over these two days is 8,938.

6 0
3 years ago
Suppose a triangle has sides a,b, and c with side c the longest side, and that a^2+b^2>c^2. Let theta be the measure of the a
andreyandreev [35.5K]

Answer :

<u>A the triangle is not a right </u><u>triangle</u>

<u>D </u><u>costheta</u><u> </u><u><0</u>

The law of cosines says:

a²=b²+c²−2bccos(θ)

Rewriting:

2bccos(θ)=b²+c²−a²<0

So cos(θ)<0cos(θ)<0 since 2bc>02bc>0. Since 0<θ<π0<θ<π in any triangle,

π/2<θ<π

So:

1. θ is not an acute angle.

2 The triangle is not a right triangle. In a right triangle, one of the angles is 90 degrees and the other two are then less than 90 degrees. This triangle has an angle greater than 90 degrees.

3. cos(θ)<0 is true.

4. cos(θ)>0 is false -3 says cos(θ) is negative; a number can't be both positive and negative.

6 0
2 years ago
Transform each polar equation to an equation in rectangular coordinates and identify its shape.
Gemiola [76]

Answer:

(a) x ^ 2 + y ^ 2 = 6 ^ 2

(b) (x-1) ^ 2 + y ^ 2 = 1

Step-by-step explanation:

Remember that to convert from polar to rectangular coordinates you must use the relationship:

x = rcos(\theta)

y = rsin(\theta)

x ^ 2 + y ^ 2 = r ^ 2

In this case we have the following equations in polar coordinates.

(a) r = 6.

Note that in this equation the radius is constant, it does not  depend on \theta.

As r ^ 2 = x ^ 2 + y ^ 2

Then we replace the value of the radius in the equation and we have to::

x ^ 2 + y ^ 2 = 6 ^ 2

Then r = 6 in rectangular coordinates is a circle centered on the point (0,0) and with a constant radius r = 6.

(b) r = 2cos(\theta)

The radius is not constant, the radius depends on \theta.

To convert this equation to rectangular coordinates we write

r = 2cos(\theta)     <em>Multiply both sides of the equality by </em><em>r</em>.

r ^ 2 = 2 *rcos(\theta)    <em>remember that</em> x = rcos(\theta), <em>then: </em>

r ^ 2 = 2x        <em>remember that </em>x ^ 2 + y ^ 2 = r ^ 2, <em>then:</em>

x ^ 2 + y ^ 2 = 2x         <em>Simplify the expression. </em>

x ^ 2 -2x + y ^ 2 = 0     <em>Complete the square. </em>

x ^ 2 -2x + 1 + y ^ 2 = 1

(x-1) ^ 2 + y ^ 2 = 1  <em>It is a circle centered on the point (1, 0) and with radio r=1</em>

6 0
3 years ago
6x-9=y ; y=-3x linear equations solution for x and y I need help can someone explain
snow_lady [41]
The answer is
 x = 1 and y = -3
<span>[1] 6x-9=y [2] y=-3x</span>
7 0
4 years ago
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