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2 years ago

Solve for x 3x+4 = (2/5)x +2

Mathematics

2 answers:

exis [7]2 years ago

4 0

I narrowed it down to 15x=2x+3 and subtract 2x

X=-10/13

julsineya [31]2 years ago

3 0

Answer:-10/13

Step-by-step explanation:

3x+4 = (2/5)x + 2

First move the 4 to the other side by subtracting it.

it becomes : 3x = (2/5)x - 2

then multiply everything by 5 to get rid of the fraction.

it becomes 15x = 2x -10

then move the 2x to the other side by subtracting it.

you get 13x = -10

now you can divide everything by 13 to isolate the x.

and you get x = -10/13

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2 years ago

Read 2 more answers

The profitability, P, of a popular restaurant franchise can be modeled by the function P (t) = t4 – 10t3 + 28t2 – 24t, where t i

vekshin1

In this question, the profit of the restaurant after t months is given by a polynomial function. To find when it begins to show a profit, we find the numerical values of the function for t, and it shows a profit when $t > 0$

Profit after t months:

$P(t) = t^4 - 10t^3 + 28t^2 - 24t$

0 months:

This is P(0). So

$P(0) = 0^4 - 10*0^3 + 28*0^2 - 24*0 = 0$

1 month:

This is P(1). So

$P(1) = 1^4 - 10*1^3 + 28*1^2 - 24*1 = -5$

2 months:

This is P(2). So

$P(2) = 2^4 - 10*2^3 + 28*2^2 - 24*2 = 0$

3 months:

This is P(3). So

$P(3) = 3^4 - 10*3^3 + 28*3^2 - 24*3 = -9$

4 months:

This is P(4). So

$P(4) = 4^4 - 10*4^3 + 28*4^2 - 24*4 = -32$

5 months:

This is P(5). So

$P(5) = 5^4 - 10*5^3 + 28*5^2 - 24*5 = -45$

6 months:

This is P(6). So

$P(6) = 6^4 - 10*6^3 + 28*6^2 - 24*6 = 0$

7 months:

This is `P(7). So

$P(7) = 7^4 - 10*7^3 + 28*7^2 - 24*7 = 175$

After 7 months it shows profit, so it starts showing profit on the 6th month, and thus, the correct answer is given by option D.

For another example of a function involving numeric value, you can check brainly.com/question/24231879

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2 years ago

Ratio Question;

SashulF [63]

*Given

Money of Phoebe - 3 times as much as Andy

Money of Andy - 2 times as much as Polly

Total money of Phoebe, - £270

Andy and Polly

*Solution

Let

B - Phoebe's money

A - Andy's money

L - Polly's money

1. The money of the Phoebe, Andy, and Polly, when added together would total £270. Thus,

B + A + L = £270 (EQUATION 1)

2. Phoebe has three times as much money as Andy and this is expressed as

B = 3A

3. Andy has twice as much money as Polly and this is expressed as

A = 2L (EQUATION 2)

4. This means that Phoebe has ____ as much money as Polly,

B = 3A

B = 3 x (2L)

B = 6L (EQUATION 3)

This step allows us to eliminate the variables B and A in EQUATION 1 by expressing the equation in terms of Polly's money only.

5. Substituting B with 6L, and A with 2L, EQUATION 1 becomes,

6L + 2L + L = £270

9L = £270

L = £30

So, Polly has £30.

6. Substituting L into EQUATIONS 2 and 3 would give us the values for Andy's money and Phoebe's money, respectively.

A = 2L

A = 2(£30)

A = £60

Andy has £60

B = 6L

B = 6(£30)

B = £180

Phoebe has £180

Therefore, Polly's money is £30, Andy's is £60, and Phoebe's is £180.

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