Answer:
75°
Step-by-step explanation:
Since the 2 angles are supplementary and TC is a perpendicular bisector, we know that m∠ATC is 90°
All we need to do is simply subtract 15° from 90° to find m∠ATB:
90 - 15 = 75°
Answer:
1. C
2. G, H
3. A, H
4. x=-4.5
5. B, D, F, G
Step-by-step explanation:
pls Mark Brainliest
Answer:
x is a variable
Step-by-step explanation:
what happens an squared plus B equals C and what I want to do is solve for a so again what we want to do is when we're taking solver a we want to isolate the variable get the variable by itself so the data that need to look at well what is happening on my variable a well you can see me as being multiplied by X and it's being added by B so I need to undo those but we got to make sure we undo them in a certain upper certain order which we call the reverse order of operations which is like the order of operations but the reverse method meaning I'm gonna undo addition or subtraction first so you can see that since my variable a is being added by B I need to undo that by subtracting B and I'll use my subtraction property of equality that's going to now subtract a 0 and then these C minus B are not like terms so I'm going to write ax is equal to C minus B now I need to solve for a so I need to look at and say alright my a is being x over X so the inverse operation of multiplying is dividing by X so therefore have a equals C minus B divided by X now sometimes you could say alright that's correct but we could also divide this X into both of these terms and I'm going to rewrite this in a different form I could say a equals C over X minus B over X alright so what I'm doing is are just dividing those through
hope this helps
Step-by-step explanation:
<em>a</em><em>)</em><em> </em><em>Four </em><em>thousand</em><em> </em><em>five </em><em>hundred</em><em> </em><em>thirty-six.</em>
<em>b)</em><em> </em><em>arrange </em><em>in </em><em>descending</em><em> </em><em>order</em>
<em>3</em><em>4</em><em>5</em><em>6</em><em>.</em>
<em>c)</em><em> </em><em>since </em><em>we </em><em>have </em><em>to </em><em>make </em><em>odd </em><em>number</em><em> </em><em>therefore</em><em> </em><em>once </em><em>digit</em><em> </em><em>will </em><em>be </em><em>odd </em><em>,</em><em> </em><em>3</em><em> </em><em>(</em><em> </em><em>or </em><em>5</em><em> </em><em>too </em><em>)</em>
<em>so,</em><em> </em><em>the </em><em>number</em><em> </em><em>is </em><em>6</em><em>5</em><em>4</em><em>3</em><em>.</em>
<em>hope </em><em>this</em><em> answer</em><em> helps</em><em> you</em><em> dear</em><em>!</em>
