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3 years ago

PLZ HELP PLZZZZZZZZZZZZZZZZ

2 answers:

7 0

The answer is a because if he has 36 cookies you start with that number. Then you don't know how many cookies he gave to his three friends so you have c as the variable that is multiplied by three. These two sets connect (36-cookies to begin with) minus(because he is giving away so he doesn't have them) and (3c-becuase 3 friends times the amount of cookies he gives each[unknown value=c])
So put together it's
36-3c

I hope that helped and wasn't to long

yKpoI14uk [10]3 years ago

4 0

Answer A. 36 minus 3c would tell you how many cookies he had left.

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Point (-5,2) is reflected over the y axis . where is the new point located ?

Ierofanga [76]

Answer:

0,-7 or anywhere i guess-

Step-by-step explanation:

4 0

3 years ago

X8>2÷(3+22+1) ⋅ 2 help me plz

s2008m [1.1K]

Answer:

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6 0

3 years ago

The amounts of Cathy’s last six clothing purchases were $109, $72, $99, $15, $99, and $89. For each question, choose the mean, m

lisov135 [29]

Answer:

The mean value = $80.5

Step-by-step explanation:

The value of her last six spendings are $109, $72, $99, $15, $99, and $89.

For the mean.

Mean = Total spendings/number

Mean =483/6

Mean = $80.5

For the median.

Lets arrange it in ascending order

$15 ,$72, $89, $99, $99, $109

The middle values are two.

Median = (89+99)/2

Median = 188/2

Median = $94

For the mode

$15 ,$72, $89, $99, $99, $109

Highest occuring is $99 with two frequencies.

To convince her parents that she needs an increase in allowance she would show them the bigger spendings .

So the least value on the list it's mean value which is $80.5.

5 0

3 years ago

Which of the following is a valid exclusion for the algebraic fraction:

erastova [34]

We have the following expression:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
Rewriting we have:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
(27a ^ 3-1) / ((3a-1) * (3a-1))
We exclude the values that make the denominator zero:
3a-1 = 0
a = 1/3
Answer:
a valid exclusion for the algebraic fraction is:
c. a ≠ 1/3

4 0

3 years ago

Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds

svetlana [45]

Answer:

Yes, but it is not linear. It is exponential : $f(x) = 5\cdot 2^{x-1}$

Step-by-step explanation:

On the first day we have 5 bacteria.

On the second day we will have 5*2 = 10 bacteria.

On the third day we will have 10*2 = 5*2*2 = 5*2^2 = 20 bacteria.

On the fourth day we will have 20*2 = 5*2*2*2 = 5*2^3 = 40 bacteria.

We can see that

$f(x) = 5\cdot 2^{x-1}$ ,

where x is a number of days and f(x) gives us the number of bacteria.

4 0

3 years ago