Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
Answer:
112
Step-by-step explanation:
srry. i meant to put 112 erlier
<span>one approach first write the formula substitute what you are given to find the rate you have the initial amount and the amount after a specified time do you see that it changed by (51 -48) millions in a period of (1997-1990) years using this rate with the new time (2017-1997) years and the new initial amount 51 million plug into the formula to find the new amount. Round your answer to the nearest million. the amount is calculated in millions. use the nearest whole number.</span>
