The value of 'y' in the given figure of parallel lines cut by a transversal will be y = 4
As per the question statement, we are given a figure of parallel lines cut by a transversal, and we are supposed to find the value of 'y'.
As per the figure,
(4x + 23) + (9x - 38) = 180 degrees [Pair of linear pair]
13x - 15 = 180
13x = 195
x = 15
Also, (4x + 23) = (21y - 1), [Pair of alternate angles]
4*15 + 23 = 21y - 1
21y = 84
y = 4
Hence, the value of 'y' in the given figure of parallel lines cut by a transversal will be y = 4.
- Parallel lines: Straight lines that are always the same distance apart from one another are called parallel lines. No matter how far apart they are, parallel lines can never come together.
To learn more about parallel lines and transversal, click on the link given below:
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This is gibberish; please be more careful how the questions look before posting. Anyway, I'll guess it says
Given OB bisects ∠AOC and OC bisects ∠BOD prove m∠AOB = m∠COD
Proof:
Statements Reasons
OB bisects ∠AOC Given
m∠AOB = m∠BOC = (1/2) m∠AOC Definition of angle bisector
OC bisects ∠BOD Given
m∠BOC = m∠COD = (1/2) m∠BOD Definition of angle bisector
m∠AOB = m∠COD transitivity of equality
The measure of the angles A, B and C are 43°, 43° and 94° respectively.
Step-by-step explanation:
- Step 1: From the given details, form equations. Let ∠A and ∠B be x°.
⇒ ∠C = 51° + x°
- Step 2: Sum of angles of a triangle is 180°
⇒ ∠A + ∠B + ∠C = 180°
⇒ x + x + 51 + x = 180
⇒ 3x + 51 = 180
⇒ 3x = 129
⇒ x = 43°
⇒ x + 51 = 94°
Answer:
My wet but, you scaliwag
Step-by-step explanation:
it simple and easy
Answer:
d is the answer of the question