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3 years ago

Solve this equation 3/5(x-10)=18-4x-1 combine like terms that are on the same side of the equation

Mathematics

1 answer:

hjlf3 years ago

6 0

Answer:

x=5

Step-by-step explanation:

3/5(x-10)=18-4x-1

3/5x-30/5=18-4x-1

3/5x-6=18-4x-1

+6 +6

3/5x=23-4x

+4x +4x

4 3/5x=23

23/5x=23

23/5 divide , so you actually multiply both sides by the reciprocal 5/23

x=5

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The circumference of a circle is 60 pi cm. What is the radius of the circle?

Artyom0805 [142]

Answer:

30/pi cm

Step-by-step explanation:

2×pi×r =60

r = 60/2×pi =30/pi

4 0

3 years ago

I need help on this problem please help

Masteriza [31]

X=36. You just make the equation: X+9=45. Then you subtract 9 from 45 like this: -9 -9. That gives you 36

5 0

3 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

3 years ago

Can someone help me please ???????

Inessa [10]

Answer:

d=1

Step-by-step explanation:

Factor d^2 - 2d - 8 into (d-4)(d+2)

Move -2/d+2 onto the other side, changing it into 2/d+2.

$\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4}+\frac{2}{d+2} = 0$

Let the empty side equal zero.

Add 3/d-4 and 2/d+2

$\frac{5d-2}{(d+2)(d-4)}$

Then add that to -3d.

$\frac{2d-2}{(d+2)(d+4)}$

Multiply 0 by d+2 and d-4 to get 2d-2 by itself.

2d=2

d=1

I can't edit the equation, but it's d-4 althroughout the question. Sorry for being so slow.

6 0

3 years ago

In the diagram the measure of angle 3 is 105 degrees which angle must also measure 105? A.1 B.4 C.6 D.8 I NEED HELP ASAP P

faltersainse [42]

Answer: The correct option is (A). angle 1.

Step-by-step explanation: In the given diagram, the measure of ∠3 is 105°.

We are to find the angle that must also measure 120°.

We know that the measures of two vertically opposite angles are equal.

In the given diagram, since ∠1 and ∠3 are vertically opposite angles.

So, the measures of ∠1 and ∠3 are equal.

That is,

m∠1 = m∠3.

Also, m∠3 = 105°.

Therefore, m∠1 = 105°.

Thus, the measure of angle 1 must be 105°.

Option (A) is correct.

4 0

3 years ago

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