This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Both are correct, since 4/6 is simplified to 2/3.
It is 5.69 positively sure of it good luck on youre quiz if youre taking one!
Here you go!! Hope my answer also assists you in the future!! :))
It's looking for the measures
m<F + m<G = 180°
(4x)° + (8x)° = 180°
12x = 180°
÷12 ÷12
x = 15
check your work
m<F + m<G = 180°
(4x)° + (8x)° = 180°
4(15)° + 8(15)° = 180°
60° + 120° = 180°
