Answer:
Find three consecutive integers where their sum is 17 less than four times the smallest integer. So consider any integer -- let's call it n.
7 answers
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1 vote:
Let the smallest of those numbers be [math]n[/math], then the other numbers w
Step-by-step explanation:
165888xy
all you do is 12^7/6^3
Answer:
Both solutions are correct
Step-by-step explanation:
Given
Expression:
See attachment for Clare and Lins' solution
Required
Determine if they are correct or not
Open bracket
Collect like terms
Divide by -3
<em>Both solutions are correct</em>
4 of you divide 6 by 1.25 it's 4.8 but for a whole bows it's 4
Take 4 and multiply it by 5 (which you should be able to do in your head) and then add the two zeros back in so:
4•5= 20
20+0+0=
2000
