Of all rectangles with a fixed perimeter of p, which one has the maximum area? (give the dimensions in terms of p.)

1 answer:

8 0

<span>For all rectangles with a fixed perimeter of p the rectangle with the maximum area is one where the length is p/4 and the width is p/4, in other words a square. The area of such a rectangle would be (p*p) /16.</span>

You might be interested in

Answer please thanks

Naddik [55]

Answer:

-37/6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The figure shows two triangles on a coordinate grid:

svet-max [94.6K]

Answer:

Whats up good luck... sorry my answer didnt submit

Step-by-stp explanation:

4 0

3 years ago

Whoever responds first will get marked best!!!!!The Garcia family is driving from 3,272 miles from San Diego, CA ot Bar Harbor,

mojhsa [17]

Answer:

Step-by-step explanation:

We know that in 5 days they have travelled 2045 miles. This means that their per day average for travel is 2045/5=409 miles per day.

Now the distance left is 3272-2045=1227 miles.

And if we divide the average miles with the miles left, it gives us= 1227/409

So, the total time taken for travel will be= 5+3=8 days

I guess this is the way to do it.

8 0

2 years ago

Read 2 more answers

If 1/2 cup of soup equals 120 milliliters, then how many milliliters are in 3 1/2 cups of soup?

pav-90 [236]

Ok. So since they give you that 1/2 cup of soup equals 120 milliliters it makes this very easy. So since we know 120milliliters=1/2 and that 3 1/2= 7 1/2s (please note that the 7 1/2s doesnt mean seven and 1/2 it means seven 1/2s) you just add 120 to itself 7 times getting an answer of 840. (please vote brainliest ^^)

8 0

3 years ago

Use the quadratic formula to find the solutions for..<br> y = 2x^2 - 9x + 5.

Yakvenalex [24]

Answer: $x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}$