First, let me introduce the general equation of the parabola:
(x-h)^2 = +/- 4a(y-k) or (y-k)^2=+/- 4a(x-h), where
(h,k) are the coordinates of the vertex a is the distance of the vertex to the focus 4a = length of lactus rectum or the focal width
If the equation contains (x-h)^2, then the parabola passes the x-axis twice. Similarly, (y-k)^2 passes the y-axis twice. If the sign is (-), it opens to the left(if y-axis) or downward (if x-axis). If the sign is (+), it opens to the right(if y-axis) or upward (if x-axis).
The equation of the parabola is -1/12 x^2 = y. Rearranging to the general form:
x^2 = -12y Therefore,
-4a = -12 4a = 12 a = 3, and the parabola is facing downwards.
The vertex is (0,0) at the origin. The focus is (0,-3). Since it is negative, the focus is situated downwards, hence -3. The directrix is the mirror image of the focus. Hence, it is a line passing +3 on the y-axis. y=3 Focal width is 4a which is equal to 12 units.
