Given function is
now we need to find the value of k such that function f(x) continuous everywhere.
We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.
So we just need to find both left and right hand limits then set equal to each other to find the value of k
To find the left hand limit (LHD) we plug x=-4 into 3x+k
so LHD= 3(-4)+k
To find the Right hand limit (RHD) we plug x=-4 into
so RHD= 
Now set both equal
k=-0.47
<u>Hence final answer is -0.47.</u>
Don’t get it show a picture or post again
Step-by-step explanation:
[(-3 × 2 × (-4)] ÷ [-6 × 12]
[3 × 2 × -4] ÷ [-6 × 12]
[6 × -4]/[-6 × 12]
-4/(-1 × 12]
-4/-12
⅓
Option A is wrong
Option B is wrong -9/-18 = ½ not ⅓
Option C is correct = -24/-72 = ⅓
Option D is wrong = 9/-18 = -½ not ⅓
Step-by-step explanation:
√a is defined only when a >= 0.
Therefore for √4x * √(x + 2) to be defined, both 4x and x + 2 must be non-negative.
When 4x >= 0, x >= 0.
When x + 2 >= 0, x >= -2.
x >= 0 and x >= -2, therefore we have x >= 0. (D)
<em>L</em><em>ook</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>h</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em>
