Let's first say that L=W+44
and then remember that perimeter is P=2L+2W
replace the L with W+44
we then get P=2(W+44)+2W, now I'll solve it
P=2W+88+2W
P=4W+88
substitute 288 for P
288=4W+88
200=4W
50=W
so now we now how wide the court is. add 44 to find the length which gives you L=94
as always plug the numbers back into your perimeter equation to ensure L and W are correct
H(17) = 17
Do you need help with the other 2?
Answer:
Both plans would cost $100 if 6 gigabytes of data are used.
Explanation:
From the question, the system of equation are correctly represented by using small letter c to represent the total cost in dollars for both equations as already assumed in the question as follows:
c = 52 + 8d ........................... (1)
c = 82 + 3d ........................... (2)
Since c is common to both, equations (1) and (2) can therefore be equated and d solved for as follows:
52 + 8d = 82 + 3d
8d - 3d = 82 - 52
5d = 30
d = 30 / 5
d = 6
Substituting d = 6 into equation (1), we have:
c = 52 + (8 * 6)
c = 52 + 48
c = 100
Since d = 6 and c = 100, it therefore implies that both plans would cost $100 if 6 gigabytes of data are used.
Answer:
The vertex is b
Step-by-step explanation:
Answer
creon queens B. lo siento is me equivoco
