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goldfiish [28.3K]
2 years ago
11

PLEASE HELP ILL GUVE EXTRA POINTS PLEASE!!!

Mathematics
2 answers:
Drupady [299]2 years ago
7 0

Answer:

\boxed{\bf 7 \times 10 {}^{ - 3}}

Step-by-step explanation:

  • \cfrac{6.3}{9}  \times \dfrac {10 ^{ - 5} }{10 {}^{ - 3} }
  • 0.7 \times  \cfrac{10 {}^{ - 5} }{10 {}^{ - 3} }
  • 0.7 \times 10  { }^{ - 5 - 3 \times  - 1}
  • 0.7 \times 10 {}^{ - 5 + 3}
  • 0.7 \times 10 { }^{ - 2}

Write 0.7 *10^-2 into scientific notation:

  • 7 \times 10 {}^{ - 3}

Hope this helps! ^^"

nata0808 [166]2 years ago
5 0

Answer:

7 \times 10^{-3}

Step-by-step explanation:

\begin{aligned}\dfrac{6.3 \times 10^{-5}}{9 \times 10^{-3}} & =\dfrac{6.3}{9} \times \dfrac{10^{-5}}{10^{-3}}\\\\& = 0.7 \times \dfrac{10^{-5}}{10^{-3}}\end{aligned}

\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\begin{aligned}\implies 0.7 \times \dfrac{10^{-5}}{10^{-3}} &=0.7 \times 10^{-5-(-3)}\\& = 0.7 \times 10^{-2}\end{aligned}

\textsf{Rewrite}\:0.7\:\textsf{as}\: 7 \times 10^{-1}:

\implies 0.7 \times 10^{-2}=7 \times 10^{-1} \times 10^{-2}

\textsf{Apply exponent rule} \quad a^b \times a^c=a^{bc}:

\implies 7 \times 10^{-1} \times 10^{-2}=7 \times 10^{-3}

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telo118 [61]

Answer:

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Step-by-step explanation:

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Answer:

25.85 years

Step-by-step explanation:

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Please help! Polygon ABCDE rotates 45° clockwise about point F to form polygon FGHIJ, shown in the figure. Find the measure of e
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Polygon FGHIJ is the result of the rotation of ABCDE. 


A = F ⇒ 117°

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D = I ⇒ 90°

E = J ⇒ 117°


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