![A = x^2](https://tex.z-dn.net/?f=A%20%3D%20x%5E2)
![B = 3x + 2](https://tex.z-dn.net/?f=B%20%3D%203x%20%2B%202)
![C = x - 3](https://tex.z-dn.net/?f=C%20%3D%20x%20-%203)
We are trying to find
, so let's simply substitute in the information we know for our variables and simplify:
![AB - C^2 = (x^2)(3x + 2) - (x - 3)^2](https://tex.z-dn.net/?f=AB%20-%20C%5E2%20%3D%20%28x%5E2%29%283x%20%2B%202%29%20-%20%28x%20-%203%29%5E2)
![3x^3 + 2x^2 - (x - 3)^2](https://tex.z-dn.net/?f=3x%5E3%20%2B%202x%5E2%20-%20%28x%20-%203%29%5E2)
- Apply the Distributive Property
![3x^3 + 2x^2 - (x^2 - 6x + 9)](https://tex.z-dn.net/?f=3x%5E3%20%2B%202x%5E2%20-%20%28x%5E2%20-%206x%20%2B%209%29)
- Simplify the last term through FOIL
![3x^3 + x^2 + 6x - 9](https://tex.z-dn.net/?f=3x%5E3%20%2B%20x%5E2%20%2B%206x%20-%209)
Our answer is 3x³ + x² + 6x - 9.
Well lets try this step by step
270/2 = 135
the cube is six sided
the answer must be 5/10 or 50 percent
You have do divide the numerator by the denominator so 3/12 =.12
After that you plug in the 4, so your answer is 4.12
only two. That is absolute value, so -3=x would be transfo into 3 by the absol values. And ofc 3=3.
so two numbers would fit as the x variable 3 and -3