Solution:
1. Consider two trees which are 5 m apart. Suppose one tree is located at a distance of 45 m from my house and another tree is located 50 m from my house. Represent , distance of two trees from my house in terms of Quadratic function.
Solution:
Let location of my house when map of planet earth is drawn or on globe=x
⇒(x-45)(x-50)=0
⇒ x² - 45 x - 50 x +45 × 50 =0
⇒ x² - 95 x + 2250=0
2. Suppose age of me and my brother is 6 and 10 years. The Product of difference between age of me and my mother who is x years old and my brother and mother is 780.Find my mother's age.
Solution: Age of my mother = x years
→(x-6) × (x-10)= 780,
if you will solve it , the value of x= 36 years
The answer would be C. 3
You find range by subtracting the highest number minus the lowest number.
Answer:
Step-by-step explanation:
PEMDAS (order of operations)
2 times 8=16
18/3= 6
16+5-6=15
You have to add them the find the reciprocal and divided to find the width then turn it to a fraction them multiply and subtract again and find your answer
By using a coordinate system I believe you can find the position of any objects on a flat surface.
If you have an eraser on your table and would like to know its position, you could make your own x and y axis and see in which quadrant your object is in.
your eraser could be 2 units in the x direction (horizontal) and 5 units in the y direction (vertical).
Now you can use this 'x and y' axis that you have drawn to locate any object.
If you want to be accurate, you should draw your axes with a meter ruler and choose your point of origin.
Hope I answered your question.
