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Reil [10]
3 years ago
15

Ross has a spinner that is split into eight equal sections numbered 1 through 8. He spun the spinner 1,104 times. Which of the f

ollowing would be a good estimate of the number of times the spinner landed on number 6?
A.
291
B.
117
C.
209
D.
127
Mathematics
2 answers:
Murljashka [212]3 years ago
8 0

Answer:

D.  127

Step-by-step explanation:

Because our spinner is split up evenly 8 ways, we a have a 1/8th chance of getting 6 with any given spin. We will want to pick the number that is the closest to one 1/8th of 1104 from our options at the right.

Let's check them one by one. Note that 1/8 as a decimal is .125, if you are using a calculator to do this problem, decimals will be fastest and we'll work with those here.

A) 291/1104 = .264

B) 117/1104 = .106

C) 209/1104 = .189

D) 127/ 1104 = .115

Our closest number to .125 (ie, 1/8th) is .115. or 127 out of 1,104 spins.

torisob [31]3 years ago
8 0

Answer:

D, 127

Step-by-step explanation:

it would be d because if the spinners each have equal spots then you can divide it by 8. which gets you 138, but that isn't an option and its probability so its always around a number. so the closest one is 127 or D

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Step-by-step explanation:

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Step 1: Write expression

\frac{\sqrt[4]{x^3} }{x^{\frac{1}{12} }}

Step 2: Rewrite radical

\frac{{(x^3)^{\frac{1}{4} }} }{x^{\frac{1}{12} }}

Step 3: Multiply powers (numerator)

\frac{{x^{\frac{3}{4} }} }{x^{\frac{1}{12} }}

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Answer:

A) The height of the trapezoid is 6.5 centimeters.

B) We used an algebraic approach to to solve the formula for b_{1}.  b_{1} = \frac{2\cdot A}{h}-b_{2}

C) The length of the other base of the trapezoid is 20 centimeters.

D) We can find their lengths as both have the same length and number of variable is reduced to one, from b_{1} and b_{2} to b. b = \frac{A}{h}

Step-by-step explanation:

A) The formula for the area of a trapezoid is:

A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2}) (Eq. 1)

Where:

h - Height of the trapezoid, measured in centimeters.

b_{1}, b_{2} - Lengths fo the bases, measured in centimeters.

A - Area of the trapezoid, measured in square centimeters.

We proceed to clear the height of the trapezoid:

1) A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2}) Given.

2) A = 2^{-1}\cdot h \cdot (b_{1}+b_{2}) Definition of division.

3) 2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}] Compatibility with multiplication/Commutative and associative properties.

4) h = \frac{2\cdot A}{b_{1}+b_{2}} Existence of multiplicative inverse/Modulative property/Definition of division/Result

If we know that A = 91\,cm^{2}, b_{1} = 16\,cm and b_{2} = 12\,cm, then height of the trapezoid is:

h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}

h = 6.5\,cm

The height of the trapezoid is 6.5 centimeters.

B) We should follow this procedure to solve the formula for b_{1}:

1) A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2}) Given.

2) A = 2^{-1}\cdot h \cdot (b_{1}+b_{2}) Definition of division.

3) 2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2}) Compatibility with multiplication/Commutative and associative properties.

4) 2\cdot A \cdot h^{-1} = b_{1}+b_{2} Existence of multiplicative inverse/Modulative property

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6) b_{1} = \frac{2\cdot A}{h}-b_{2} Existence of additive inverse/Definition of subtraction/Modulative property/Result.

We used an algebraic approach to to solve the formula for b_{1}.

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1) A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2}) Given.

2) b_{1} = b_{2} Given.

3) A = \frac{1}{2}\cdot h \cdot (2\cdot b) 2) in 1)

4) A = 2^{-1}\cdot h\cdot (2\cdot b) Definition of division.

5) A\cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot b Commutative and associative properties/Compatibility with multiplication.

6) b = A \cdot h^{-1} Existence of multiplicative inverse/Modulative property.

7) b = \frac{A}{h} Definition of division/Result.

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