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Neporo4naja [7]
2 years ago
11

Help please! Select the correct answer.

Mathematics
2 answers:
zhenek [66]2 years ago
5 0
The answer to your problem is letter B
Nezavi [6.7K]2 years ago
4 0
The answer to your problem is b
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The city of Jasper has a water tower that holds 1,325,000 gallons of water. Express this number in scientific notation.
Tatiana [17]

B one is the is the answer bcoz it is positive

7 0
3 years ago
Read 2 more answers
Mr. Thompson had a balance of $283.12 in his checking account at the beginning of the month he wrote checks for $23.09 $7.56 $12
ryzh [129]

Account balance is $123.08

Step-by-step explanation:

  • Step 1: Balance in Thompson's account = $283.12. Calculate the total amount of checks Thompson wrote in the month.

Total amount of checks = $23.09 + $7.56 + $125.11 + $4.28

                                        = $160.04

  • Step 2: Calculate his balance.

Account balance = $283.12 - $160.04

                            = $123.08

8 0
3 years ago
What is anequation of the line that passes through the points (-3, 8) and (-7,8)?
zaharov [31]

The equation of a line is given by the expression:

y=Mx + b

This is the slope form of an equation where M is the gradient of line and b is the y intercept.

For the slope, M= change in y values/ change is x values

(-3,8) , (-7,8) thus the slope m,=(8-8)/(-7--3)

m=0/-4 =0

the slope is 0

To find the b substitute the values in the equation y=Mx+b

Taking point (-3,8) and slope of 0

y=Mx+b

8=0*(-3) + b

8=0+b

8=b

The value of b is 8

The equation of the line will be;

y-8=0(x+3)y-8=0y=8

The equation of the line is y=8

7 0
1 year ago
The theorems in this lesson relate to all of the following:
grin007 [14]

Answer:

tangents, arcs, and chords

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
if a and b are acute angles such that sinA=4/5 and cosB=12/13, calculate, without using tables: sin(a-b)
kolbaska11 [484]
\sin \alpha = \frac{4}{5} \\ \cos \alpha  =  \sqrt{1-\sin^2 \alpha }= \sqrt{1- \frac{16}{25} }   = \sqrt{ \frac{9}{25} }= \frac{3}{5} \\    \\ \cos \beta = \frac{12}{13}  \\  \sin \beta  =  \sqrt{1-\cos^2  \beta }= \sqrt{1- \frac{144}{169} }   = \sqrt{ \frac{25}{169} }= \frac{5}{13}


\\  \\ \sin (\alpha- \beta ) =\sin \alpha \cos \beta -\cos \alpha \sin \beta = \frac{4}{5}\times \frac{12}{13}-   \frac{3}{5}\times \frac{5}{13} =  \frac{48}{65}- \frac{15}{65}=  \frac{33}{65}

Answer:
sin(α-β) = 33/65
7 0
3 years ago
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