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Lubov Fominskaja [6]
3 years ago
5

The annual health insurance premium for Ms. Everett is $12,304 her employer says 70% of the premium and deducts the remainder fr

om her paycheck Ms. Everett is paid monthly what amount is deducted from Ms. Everett paycheck for her health insurance premium.
$141.97
$307.60
$331.26
$717.73
Mathematics
1 answer:
Mazyrski [523]3 years ago
4 0
Ms. Everett will be responsible for paying 30% of her annual premium of $12,304.  (12,304 X .30)

Her portion will be $3,691.20

If you spread that out over 12 months (3,691.20/12) it comes out to $307.60
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2 years ago
The graph of a function f(x) is shown below:<br><br><br><br> What is the domain of f(x)?
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The domain is the scope of the x values. In this case (-2,-1) is a hole, so x>-2 is one end of the domain, while (3,3) is defined. So the domain using interval notation is (-2,3] which can also be expressed -2 < x ≤ 3, answer option 1

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3 years ago
What is the cheapest way to buy 48 cans of cola
Inga [223]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
What is the sum of the prime factors of 2014
goblinko [34]

The sum of prime factors of 2014 is 74

<h3><u>Solution:</u></h3>

Given that to find sum of prime factors of 2014

Let us first find the prime factors of 2014

A prime number is a whole number greater than 1 whose only factors are 1 and itself

"Prime Factorization" is finding which prime numbers multiply together to make the original number.

<em><u>Prime factors of 2014:</u></em>

The Prime Factorization is:

2014 = 2 \times 19 \times 53

Thus the prime factors of 2014 are 2, 19, 53

<em><u>Let us now find the sum of prime factors of 2014</u></em>

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7 0
3 years ago
Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t
Amanda [17]

Answer:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

df = n-1= 22-1=21

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

\bar X=33.9 represent the sample mean

s=4.1 represent the sample standard deviation

n=22 sample size  

\mu_o =26 represent the value that we want to test

\alpha=0.025 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:  

Null hypothesis:\mu \geq 36  

Alternative hypothesis:\mu < 36  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

Now we can calculate the critical value but first we need to find the degreed of freedom:

df = n-1= 22-1=21

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

3 0
3 years ago
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