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Eva8 [605]
2 years ago
7

I'm so confused. Really need help! Brainliest + points

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
8 0
What do u need help with? And what are you confused about I’m here to help let me k ow what you need help with so I can see if I can help or not.
You might be interested in
Coefficient of x^2 in expansion of (x+2)^5
iVinArrow [24]
The x² term will be C(5,2)x²·2³ = 80x².

The coefficient is 80.

_____
C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5·4/(2·1) = 10
8 0
3 years ago
PLEASE HELP!!!!! HURRY
svp [43]
Its c first find area of the whole thing with piece cut out.(240) then of the cut out piece (12) 240-12=228 C
7 0
3 years ago
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\

\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
3 years ago
6. Choose the correct common fraction.<br> 1/2<br> 2/3<br> 0.1<br> 0.5
ira [324]

Answer:

1/2 most likely everyone says "half" instead on "point five"

8 0
2 years ago
Read 2 more answers
PLZ HURRY IT'S URGENT!!
Alexus [3.1K]
The answer is 6/7 or 5/6 idk but pic would help
5 0
3 years ago
Read 2 more answers
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