<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.
We require B(n) = 0...i.e. balance of 0 after n months.
so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
Then, with some algebraic juggling we get:
n = -[log(1 - (Ai/P)]/log(1 + i)
Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43
Also, i = (13.6/100)/12 => 0.136/12 per month
i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)
so, n = 4.15 months...i.e. 4 payments + remainder
b) Now we have A = $754.43 - $300 = $454.43 so,
n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)
so, n = 1.54 months...i.e. 1 payment + remainder
</span>
Answer:
15v^5+4v^3-24v^2
Step-by-step explanation:
Distribute the Negative Sign:
=3v5+8v3−10v2+−1(−12v5+4v3+14v2)
=3v5+8v3+−10v2+−1(−12v5)+−1(4v3)+−1(14v2)
=3v5+8v3+−10v2+12v5+−4v3+−14v2
Combine Like Terms:
=3v5+8v3+−10v2+12v5+−4v3+−14v2
=(3v5+12v5)+(8v3+−4v3)+(−10v2+−14v2)
=15v5+4v3+−24v2
Answer:
=15v5+4v3−24v2
Hope this helps! :)
Answer:
D is the correct answer
Step-by-step explanation:
first you subtract the 3 from the left side and add it to the right side. then you divide both side by negative 3 and flip the less than sign to a greater than sign
According to the statement 160 books were given to the class.
The correct option is C.
<h3>What is linear equation?</h3>
One or two variables make up a linear equation. Neither the numerator nor the denominator of a fraction can be a variable in a linear equation raised to a power higher than 1. All of the points on a coordinate grid sit on the same line when you identify the values that together make a linear equation true and plot those values.
<h3>According to the given information:</h3>
Let the no. of students be s:
Let the no. of books be b:
Given that there will be 20 books left after each student selects 4 books,
b = 4s + 20
And the remaining students take 5 books each, therefore b=5(s3), even if 3 pupils choose not to take a book.
comparing the value b
4s+20=5(s−3)
4s+20=5s−15
s=20+15
s=35
To do this, change the value of s in b=4s+20 to what is shown below:
b=4(35)+20
b=140+20
b=160
160 books were given to the class.
To know more about linear equation visit:
brainly.com/question/766814
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