A_n= a₁+(n-1)d
a₁ first term
n terms
d distance between each value
a_n= 12+(405-1)(5)=2032
The last option because it’s the one that makes that will get you the sum need when added with the other polynomial
Answer:
The modulus of the complex number 6-2i is:

Step-by-step explanation:
Given the number

We know that
where x and y are real and 
The modulus or absolute value of z is:

Therefore, the modulus of
will be:










Therefore, the modulus of the complex number 6-2i is:
