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ivann1987 [24]
3 years ago
11

Divide -2x3-5x2+4x+2 by x+2

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0
It would be -26

Its very easy But you will get better =)

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This is problem six of the homework that you ask for
Marina86 [1]
This equation could represent the relationship e=8.75h
8 0
3 years ago
Simplify 3a^2b^2x2ab+6a^3b^2
ira [324]

3 {a}^{2} \times  {b}^{2} \times 2ab + 6 {a}^{3} \times  {b}^{2} =

6 {a}^{3} {b}^{3} + 6 {a}^{3} {b}^{2} =

Factoring 6a^3 b^2

6 {a}^{3} {b}^{2}(b + 1)

_________________________________

I think this is the correct answer.

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0
3 years ago
Which cylinder pressure will Jillian need if she plans to fill 90 balloons?
LiRa [457]

Answer:

C

Step-by-step explanation:

Because if she wants to fill 90 balloons 100 is 30 so multiply by 30×3 and u get 90

5 0
3 years ago
How do i solve this?
Law Incorporation [45]

Answer:

\large\boxed{x

Step-by-step explanation:

-\dfrac{1}{2}x+\dfrac{1}{3}>\dfrac{3}{5}\\\\\text{Find common denominator of the fractions}\\\\2,\ 3,\ 5\to2\cdot3\cdot5=30\\\\-\dfrac{1}{2}x+\dfrac{1}{3}>\dfrac{3}{5}\qquad\text{multiply both sides by 30}\\\\30\!\!\!\!\!\diagup^{15}\left(-\dfrac{1}{2\!\!\!\!\diagup_1}x\right)+30\!\!\!\!\!\diagup^{10}\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)>30\!\!\!\!\!\diagup^{6}\left(\dfrac{3}{5\!\!\!\!\diagup_1}\right)\\\\-15x+10>(6)(3)\\\\-15x+10>18\qquad\text{subtract 10 from both sides}

-15x>8\qquad\text{change the signs}\\\\15x

4 0
4 years ago
Construct a 96% confidence interval if a sampling distribution has a mean of 20, a standard deviation of 5, and a size of 100.
MAXImum [283]

Using the t-distribution, the 96% confidence interval is given as follows:

(18.96, 21.04).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 96% confidence interval, with 100 - 1 = 99 df, is t = 2.0812.

The parameters are given as follows:

\overline{x} = 20, s = 5, n = 100

Hence the bounds of the interval are:

\overline{x} - t\frac{s}{\sqrt{n}} = 20 - 2.0812\frac{5}{\sqrt{100}} = 18.96

\overline{x} + t\frac{s}{\sqrt{n}} = 20 + 2.0812\frac{5}{\sqrt{100}} = 21.04

More can be learned about the t-distribution at brainly.com/question/16162795

#SPJ1

6 0
2 years ago
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