Question

Use Plank’s constant, 6.626 × 10-34, to solve the following:

Answer 1

Answer:

B. $3.78 \times 10^{-19}$ J

Explanation:

Energy (E) = Planck's constant (h) × Frequency (ν)

1 Hertz = 1 $s^{-1}$  

So Hertz and $s^{-1}$ are equal

$E=6.626 \times 10^{-34} Js \times 5.71 \times 10^{14} s^{-1}$

(s and $s^{-1}$ gets cancel as both are in the numerator leaving behind Joules)

$=37.8 \times 10^{-20} J$

(Moving the decimal point to the left one place power of 10 increases from -20 to - 19)

$= 3.78 \times 10^{-19}$ J (Answer)

Answer 2

Answer:

E= h*frequency

6.626*10^-34)*5.71*10^14)= 3.78*10^-19 J