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sveta [45]
3 years ago
13

What are the factors of 3x^2 + 23x − 8?

Mathematics
1 answer:
Margaret [11]3 years ago
8 0
<span>3x</span>²<span> + 23x − 8 = 3x</span>² + 24x - x - 8 = 3x(x+8) - (x+8) = (x+8)(3x-1)
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The real part of the complex number –5 + 3i is
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Simplify polynomial
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Answer:

j² - 5j²k - 2

Step-by-step explanation:

3j² - j²k - 6 - 4j²k - 2j² + 4

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We have three groups of like terms:

The j-squares (j²), the j-squared k (j²k) and the constants (no variable).

Remember to include the negatives!

The j-squares are: 3j² ; -2j²

The j-squares k are: - j²k ; - 4j²k

The constants are: - 6 ; 4

Simplify:

3j² - j²k - 6 - 4j²k - 2j² + 4

Rearrange the polynomial by like terms

= (- j²k - 4j²k) +  (3j² - 2j²) + (- 6 + 4)

Add or subtract the like terms

= (-5j²k) + (j²) + (-2)

Remove brackets and rearrange so the negative is not first

= j² + - 5j²k + - 2

Simplify where two signs are together. Adding a negative is subtraction.

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