After getting a job at the ice cream parlor, Mitzi put $20 in

Which number is not a solution to the inequality below? x<15 A -6 B -2 C 11 D 17 Please help! Thanks

Svetach [21]

Answer:

D.17

Step-by-step explanation:

We are given that inequality

x<15

We have to find the number which is not a solution of the given inequality.

x<15

It means the values of x which is less than 15.

A.-6

-6<15

Therefore, it is the solution of given inequality.

B.-2

-2<15

Therefore, it is the solution of given inequality.

C.11

11<15

Therefore, it is the solution of given inequality.

D.17

17>15

Therefore, it is not a solution of given inequality.

Option D is true.

6 0

2 years ago

Use the x-intercept method to find all real solutions of the equation. -9x^3-72x^2+36=3x^3+x^2-3x+8

larisa86 [58]

-9x^3-72x^2+36=3x^3+x^2-3x+8 Add 9x^3 to both sides.

-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8 Add 72x^2 to both sides

36 = 12x^3 + 73x^2 - 3x + 8 Subtract 36 from both sides.

0 = 12x^3 + 73x^2 - 3x - 28

It does factor, but it is not very nice.

(x + 6.06)(x - 6.09)(x + 0.632)

If there is any kind of error please report it in a note below.

6 0

3 years ago

Which expressions are equivalent to √/32? 4√8 08 2√8 4√2 16 16√2

vaieri [72.5K]

Answer: 4√2

square root of a number is the factor that we can multiply by itself to get that number.

The square root symbol is also called as a RADICAL.

Perfect squares are the squares of the integers also called as square numbers.

to find the square root of non-perfect squared numbers we have to check the number with a near-perfect squared numbers

how to find square root of non perfect squared numbers:

If we can't figure out what factor multiplied by itself will result in the given number, we can make a factor tree.

Factor tree of 32 = 2*2*2*2*2

= (2*2) * (2*2) *2

= (4)2 *2

Therefore √/32 = √/2*2*2*2*2

= √/(4)2*2

= 4√/2

learn more about square roots here:

brainly.com/question/428672

brainly.com/question/3617398

#SPJ9

8 0

1 year ago

For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4

Elina [12.6K]

Answer:

C. $(5-\frac{1}{2})^6$

Step-by-step explanation:

Given

$15(5)^2(-\frac{1}{2})^4$

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

$Sum = 2 + 4$

$Sum = 6$

Each term of a binomial expansion are always of the form:

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

Where n = the sum above

$n = 6$

Compare $15(5)^2(-\frac{1}{2})^4$ to the above general form of binomial expansion

$(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......$

Substitute 6 for n

$(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......$

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

and

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

We have;

$^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4$

Further comparison gives

$^nC_r = 15$

$a^{n-r} =(5)^{6-4}$

$b^r= (-\frac{1}{2})^4$

[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

$a = 5$

$n = 6$

$r = 4$

[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

$r = 4$

$b = \frac{-1}{2}$

Substitute values for a, b, n and r in

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

$(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

Solve for $^6C_4$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

Check the list of options for the expression on the left hand side

The correct answer is $(5-\frac{1}{2})^6$

3 0

3 years ago

What is the value of 7^2-3^3

lbvjy [14]

Answer:

22

Step-by-step explanation:

7^2-3^3

(7)(7)-(3)(3)(3)

49-(3)(9)

49-27

22

3 0

2 years ago